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bija089 [108]
2 years ago
15

Name two lines in the diagram. Four horizontal lines are shown. At the top is line upper M upper A. Next is line upper L upper B

. Next is line upper K upper C. At the bottom is line upper J upper D. Two transversals cut through these lines. One passes through points upper M, upper L, upper K, and upper J. The other passes through points upper A, upper B, upper C, and upper D.The transversal on the left crosses the top horizontal line at point Upper M, the horizontal line second from the top at point Upper L, the horizontal line third from the top at point Upper K, and the bottom horizontal line at point Upper J. The transversal on the right crosses the top horizontal line at point Upper A, the horizontal line second from the top at point Upper B, the horizontal line third from the top at point Upper C, and the bottom horizontal line at point Upper D.
A. modifying above upper J upper K with bar, modifying above upper L upper B with bar
B. modifying above upper M upper A with one-way arrow, modifying above upper J upper D with one-way arrow
C. modifying above upper K upper C with two-way arrow, modifying above upper D upper A with two-way arrow
D. modifying above upper M upper J with two-way arrow, modifying above upper E upper F with two-way arrow
Mathematics
1 answer:
levacccp [35]2 years ago
8 0

Answer:

C. KC DA

Step-by-step explanation:

KC is across each other and DA is up and down from each other.

Hope this helps :)

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Part B) A=\$22,304

Part C) The graph in the attached figure

Step-by-step explanation:

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The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

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A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

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in this problem we have  

t=20\ years\\ P=\$8,500\\ r=0.0812\\n=12  

substitute in the formula above  

A=8,500(1+\frac{0.0812}{12})^{12*20}  

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Part B) What if the deposit were compounded monthly with simple interest?  

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

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substitute in the formula above

A=8,500(1+0.0812*20)

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A(t)=8,500(1+0.0812t)  -----> equation B

using a graphing tool  

see the attached figure  

Observing the graph, from the second year approximately the monthly compound interest is better than the simple interest.

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