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Aleonysh [2.5K]
3 years ago
10

Use the formula to find the midpoint between a segment with endpoints (0,5) and (-4, 6). *

Mathematics
2 answers:
kicyunya [14]3 years ago
5 0

Answer:

Step-by-step explanation:

(x₁ ,y₁) = (0 , 5)   & (x₂, y₂) = (-4 , 6)

Midpoint = (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})\\\\

               = (\frac{0 - 4}{2} , \frac{5+6}{2}) \\\\= (\frac{-4}{2} , \frac{11}{2})\\\\=(-2 , 5.5)

               

Lelechka [254]3 years ago
4 0

The mid-point is the average of the respective values for x and y.

So, the formula for the mid-point would be: (\frac{x_{2} + x_{1}}{2}, \frac{y_{2} + y_{1}}{2})

So for your problem this would be:(\frac{-4}{2}, \frac{11}{2})

So the final answer would be: (-2, 5.5)

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PLEASE HELP I NEED THIS NOW SO BADLY :(( Simplify: 2 1/4 x+(4 1/3 x−7 4/5 )÷2 3/5
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Answer:

2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}

Step-by-step explanation:

Considering the expression

2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}

Simplifying the expression

\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{1}{4}=\frac{9}{4}

\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{3}{5}=\frac{13}{5}

\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 4\frac{1}{3}=\frac{13}{3}

\frac{9}{4}x+\left(\frac{13}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 7\frac{4}{5}=\frac{39}{5}

\frac{9}{4}x+\left(\frac{13}{3}x-\frac{39}{5}\right)\div \frac{13}{5}

As

\frac{9}{4}x=\frac{9x}{4}

and

\frac{\frac{13}{3}x-\frac{39}{5}}{\frac{13}{5}}=\frac{5\cdot \frac{65x-117}{15}}{13}

So,

\frac{9x}{4}+\frac{5\cdot \frac{65x-117}{15}}{13}

\mathrm{Least\:Common\:Multiplier\:of\:}4,\:13:\quad 52

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

\frac{117x}{52}+\frac{\frac{4\left(65x-117\right)}{3}}{52}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

\mathrm{Join}\:117x+\frac{4\left(65x-117\right)}{3}:\quad \frac{611x-468}{3}

\frac{\frac{611x-468}{3}}{52}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

\frac{611x-468}{3\cdot \:52}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:52=156

\frac{611x-468}{156}

\mathrm{Factor}\:611x-468:\quad 13\left(47x-36\right)

\frac{13\left(47x-36\right)}{156}

\mathrm{Cancel\:the\:common\:factor:}\:13

\frac{47x-36}{12}

Therefore, 2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}

Keywords: algebraic expression , simplification

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

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Step-by-step explanation:

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15, 22, 37, 49, 82

From this arrangement, we can see that 37 is the middle number making it the median.

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Step-by-step explanation:

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Domain: -4, -1, 6, 8, 9

Range: -2, 0, 4, 5

Domain can easily be found by looking through the set's x-coordinates.

Range can be found on the y-coordinates.

Repeating numbers just needs one number to be listed (Ex. the range has two 4's but there is only one 4 listed).

Write them in order.

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4 years ago
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