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3 years ago

John can fly his airplane 2740 miles with a wind speed of 75 mph in the same time he can travel 2140 miles

Mathematics

1 answer:

posledela3 years ago

5 0

Step-by-step explanation:

with the wind

x+75=2740

against the wind

x-75=2140

from both 2x=4880

x=2440

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a lakeis 200ft wide. two boats start to move towards one another from opposite shores.In one minute ,the first boat goes 40 ft a

IrinaVladis [17]

The distance between the boats after 1 minute would be 130 ft.

Given that a lake is 200ft wide, and two boats start to move towards one another from opposite shores, and in one minute, the first boat goes 40 ft and the second one goes 30 ft, to determine what would be the distance between the boats after 1 minute the following calculation must be performed:

Total width - boat distance 1 - boat distance 2 = Distance after 1 minute
200 - 40 - 30 = X
130 = X

Therefore, the distance between the boats after 1 minute would be 130 ft.

Learn more about maths in brainly.com/question/25808345

6 0

2 years ago

Please solve with explanation I’ve been asking all day (this is not a multiple choice question)

Anastaziya [24]

Answer:

a) $SA = 522.9~cm^2$

b) $V_{cone} = 670.2~cm^3$

c) $V_{empty} = 1340.4~cm^3$

Step-by-step explanation:

For a cone,

$SA = \pi r (L + r)$

where L = slant height

$L = \sqrt{r^2 + h^2}$

We have r = 8 cm; h = 10 cm

$L = \sqrt{(8~cm)^2 + (10~cm)^2}$

$L = \sqrt{164~cm^2}$

$SA = (\pi)(8~cm)(\sqrt{164~cm^2} + 8~cm)$

$SA = 522.9~cm^2$

$V_{cone} = \dfrac{1}{3}\pi r^2 h$

$V_{cone} = \dfrac{1}{3}(\pi)(8~cm)^2(10~cm)$

$V_{cone} = 670.2~cm^3$

$V_{cylinder} = \pi r^2 h$

empty space = volume of cylinder - volume of cone

$V_{empty} = V_{cylinder} - V_{cone}$

$V_{empty} = \pi r^2 h - \dfrac{1}{3}\pi r^2 h$

$V_{empty} = (\pi)(8~cm)^2(10~cm) - \dfrac{1}{3}(\pi)(8~cm)^2(10~cm)$

$V_{empty} = 1340.4~cm^3$

3 0

3 years ago

Please help me with precal

Doss [256]

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