Answer:
![\sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
Step-by-step explanation:
![x^{2/3} = \sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=x%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
Let the present age of student be x
Present of teacher will be 4x
After 20 years,
Age of student = x + 20
Age of teacher = 4x + 20
According to the given condition after 20 years,
x + 20 = (4x + 20)/2
x + 20 = 2x + 10
2x - x = 20 - 10
x = 10
So student's present age is 10 years while teacher's is 4 x 10 i.e 40 years.
Hope This Helps You!
Whats the expression so you can plug those numbers in.
Answer:
first figure out what v is then add it with 2 then compare
Step-by-step explanation:
17-6×10÷2+12
Apply bodmas
=17-6×5+12
=17-30+12
=17-18
=-1
