2 years ago

WILL MARK BRAINLIST

Mathematics

1 answer:

netineya [11]2 years ago

8 0

56 because of the formula and the misadventure amount it

You might be interested in

How would you describe the correlation in the data? Explain your reasoning.

OleMash [197]

Answer:

Where is the options

Step-by-step explanation:

7 0

3 years ago

6 millimeters = yards

sertanlavr [38]

6 millimeters equals 0.00656168 yards.

7 0

3 years ago

Willian and Amy are stuffing envelope for a charity today, William stuff a total of 70 envelope. This is 10 more than twice the

LiRa [457]

Answer:

because it is 10 major then we remove those ten and it gives us 60 that between 2 is 30 :))

7 0

2 years ago

Find the extreme values of f(x y)=xy subject to the constraint x^2 + y^2 -4 = 0

KATRIN_1 [288]

Via Lagrange multipliers:

$L(x,y,\lambda)=xy+\lambda(x^2+y^2-4)$

$L_x=y+2\lambda x=0$
$L_y=x+2\lambda y=0$
$L_\lambda=x^2+y^2-4=0$

$yL_x=y^2+2\lambda xy=0$
$xL_y=x^2+2\lambda xy=0$
$\implies yL_x-xL_y=y^2-x^2=0\implies y^2=x^2$
$\implies x^2+y^2=4=2x^2\implies x^2=2\implies x=\pm\sqrt2\implies y=\pm\sqrt2$

So we have four critical points to consider, $(\sqrt2,\sqrt2),(-\sqrt2,\sqrt2),(\sqrt2,-\sqrt2),(-\sqrt2,-\sqrt2)$ . If both coordinates are positive or both are negative, we get a maximum value of $(\pm\sqrt2)^2=2$ ; otherwise, we get a minimum of $(-\sqrt2)(\sqrt2)=-2$ .

4 0

3 years ago

An unknown number y is 15 more than an unknown number x. The number y is also x less than 8. The equations to find x and y are s

melomori [17]

Add the equations to eliminate x

6 0

2 years ago

Read 2 more answers