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3 years ago

Find the measure of each numbered angle for each figure

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

Answer:

Angle 1 is 58. Angle 2 is 32.

Step-by-step explanation:

The measure of Angle ACB is 90 because C is on the circle and A and B connect to form a diameter of the circle. So, Angle 1 and Angle 2 add up to 90 (total degrees in triangle - 90). Now you can add the expressions the question gave for Angle 1 and Angle 2, and you get 7x + 6. So you have the equation 7x + 6 = 90. Solve the equation and you get x = 12. Now you can plug in that value for x into the expressions for Angles 1 and 2 to find their measures.

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Marisa bought four bottles of water.Each bottle of water was 95 cents. Write an equation with the same product as the total cost

meriva

Answer:

$5\times 0.76= 3.8$

Step-by-step explanation:

Given: Marisa bought four bottles

Price of each bottle is $0.95.

Solving with the factors as given to find the total cost paid by Marisa.

Total cost= $4\ bottles\times \$ 0.95= \$ 3.8$

∴ Total cost paid by Marisa is $3.8.

As given to write an equation with the same product as the total cost but different factors.

∴ Lets assume the number of bottles bought by Marisa be "5" and cost of each bottle be "x"

We already find the total cost she paid is $3.8.

Now, writing an equation with different factors, as total cost remain same.

$5\times x= 3.8$

Dividing both side by 5

we get x= $ 0.76

∴ The required equation is $5\times 0.76= 3.8$

6 0

3 years ago

What is bigger 5/6 or 11/12?

Maurinko [17]

First you find the common deoninator.
Step 1: Reduce (simplify) entered fractions to lowest terms, if the case:Fraction: 5 / 6 it's already reduced to lowest terms
Fraction: 11 / 12 it's already reduced to lowest terms
Step 2: Calculate LCM (lowest common multiple) of the reduced fractions' denominators, it will be the common denominator of the compared fractions:Denominator 6, factored = 2 * 3
Denominator 12, factored = 22 * 3
LCM (6, 12) = 22 * 3 = 12Step 3: Calculate each fraction's expanding number (LCM divided by each fraction's denominator):For fraction: 5 / 6 is 12 : 6 = (22 * 3) : 6 = 2
For fraction: 11 / 12 is 12 : 12 = (22 * 3) : 12 = 1
Step 4: Expand fractions to bring them to the common denominator (LCM):5 / 6 = (2 * 5) / (2 * 6) = 10 / 12
11 / 12 = (1 * 11) / (1 * 12) = 11 / 12

4 0

2 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

This is the last one!

elixir [45]

I think is C or D, but I'm not to sure

7 0

3 years ago

What is the product of the rational expression?? CORRECT ANSWER'S ONLY

padilas [110]

The answer is B.

Breaking down the operation:

NUmerators: x × x = x² and +3 × -3 = -9

Denumerators: x × x = x² and +2 × -2 = -4

Answer:

$\frac{x+3}{x+2}$ × $\frac{x-3}{x-2}$

Hope it helped,

Happy homework/ study/ exam!

7 0

2 years ago