Pls give this a 5 star rating lol
I was just in the same situation, you got this. the answer is A.
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:

Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:


Now we can apply the quadratic formula

where a=-16, b=122, and c=198


or


or


or

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
The answer is C. I got this by doing a^2 + b^2= c^2. 50^2 + 16^2=c^2, 2500 + 256 = c^2, 2756 = c^2, then you take the square root of 2756 and that gives you your answer 52.50 yards. Hope this helps :D
Answer:
Sorry but we need more info.
Step-by-step explanation:
:)