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3 years ago

What is the first step you will use to solve this equation: 4x +2 = 7x - 13

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

6 0

I would subtract 4x from 7x to get x on one side.

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URGENT PLEASE HELP!!!

ycow [4]

X
$x \frac{1}{6} + 2x \frac{2}{3}$

5 0

3 years ago

I attached the question in the image below

djyliett [7]

Answer:

45°

Step-by-step explanation:

$tan^{-1}(1)$ = 45°

8 0

3 years ago

Read 2 more answers

The URS construction company has submitted two bids, one to build a large hotel in London and the other to build a commercial o

topjm [15]

Answer: Our required probability is 0.55.

Step-by-step explanation:

Since we have given that

Probability that chance of winning the hotel bid = 40%

Probability that no chance of winning the hotel bid = 100-40=60%

Probability that chance of winning the office building bid = 25%

Probability that no chance of winning the office building bid = 100-25 = 75%

So, Probability that the company will win at least one contract is given by

$0.4\times 0.75+0.6\times 0.25+0.4\times 0.25\\\\=0.55$

Hence, our required probability is 0.55.

5 0

3 years ago

1. If the spinner below is spun once, find each <br> probability.

CaHeK987 [17]

Answer:

I don't know what kind of questions is this but first you need to show your spinner

6 0

3 years ago

General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

4 years ago