How do I solve this problem

Mathematics

1 answer:

aev [14]3 years ago

4 0

-1 > (x + 4) / 2....multiply both sides by 2, eliminating the 2 on the right
2 * -1 > x + 4
-2 > x + 4 ....subtract 4 from both sides
-2 - 4 > x
-6 > x or x < -6

graphed : open circle (because there is no equal sign)...on -6, shading to the left

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A box contains five slips of paper, marked $1, $1, $10, $10, and $25. The winner of a contest selects two slips of paper at rand

Leni [432]

Answer:

P(w = $1) = 1/10

P(w = $10) = 5/10

P(w = $25) = 4/10

Step-by-step explanation:

Let S1, S2, S3, S4 and S5 be the slips of paper, where we make the next identifications

S1: $1, S2: $1, S3: $10, S4: $10 and S5: $25. The number of different subsets of size 2 that we can get with the five slips of paper is given by 5C2 = 10 (combinations). Let's define the following events

A: the winner of the contest gets $1

B: the winner of the contest gets $10

C: the winner of the contest gets $25

So,

A={(S1, S2)}

B={(S1, S3), (S2, S3), (S1, S4), (S2, S4), (S3, S4)}

C={(S1, S5), (S2, S5), (S3, S5), (S4, S5)}

The random variable w can only take the values $1, $10 or $25. Then

P(w = $1) = P(A) = 1/10

P(w = $10) = P(B) = 5/10

P(w = $25) = P(C) = 4/10

3 0

3 years ago

Can someone explain which one it is and how they got the answer

VladimirAG [237]

Option D:

Measure of arc BEC = 228°

Solution:

Given angle A = 114° and vertical angle of A = 0.

<em>If two chords intersect inside the circle, then the measure of each angle is one half of the sum of the measures of the arcs intercepted by the angle and its vertical angle.</em>

$$\Rightarrow \angle A = \frac{1}{2} (ar \ BEC + vertical \ ar A)$