Michelle(1)+bros(2)+sisters(3)+mom(1)+Pop(1)=8
3/4 of 8 = 6
So, 6 people in Michelle's family like to go swimming
I will solve your system by substitution.<span><span>x=<span><span>3y</span>−1</span></span>;<span><span><span>5x</span>−<span>7y</span></span>=19</span></span>Step: Solve<span>x=<span><span>3y</span>−1</span></span>for x:Step: Substitute<span><span>3y</span>−1</span>forxin<span><span><span><span>5x</span>−<span>7y</span></span>=19</span>:</span><span><span><span>5x</span>−<span>7y</span></span>=19</span><span><span><span>5<span>(<span><span>3y</span>−1</span>)</span></span>−<span>7y</span></span>=19</span><span><span><span>8y</span>−5</span>=19</span>(Simplify both sides of the equation)<span><span><span><span>8y</span>−5</span>+5</span>=<span>19+5</span></span><span>(Add 5 to both sides)
</span><span><span>8y</span>=24</span><span><span><span>8y</span>8</span>=<span>248</span></span>(Divide both sides by 8)<span>y=3</span>Step: Substitute3foryin<span><span>x=<span><span>3y</span>−1</span></span>:</span><span>x=<span><span>3y</span>−1</span></span><span>x=<span><span><span>(3)</span><span>(3)</span></span>−1</span></span><span>x=8</span><span>(Simplify both sides of the equation)</span><span>
x=<span><span>8<span> and </span></span>y</span></span>=3
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3)
The density of silver is 10.5g/cm^3
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2)
Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3
Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2)
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
