Answer:
15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 25 charged purchases and a standard distribution of 2
This means that
Proportion above 27
1 subtracted by the pvalue of Z when X = 27. So
has a pvalue of 0.8413
1 - 0.8413 = 0.1587
Out of the total number of cardholders about how many would you expect are charging 27 or more in the study?
0.1587*100% = 15.87%
15.87% of the total number of cardholder would be expected to be charging 27 or more in the study.
Hey there!
When we multiply fractions and whole numbers, we simply take that whole number and put it over them, and just multiply across. That gives us:
Notice how it's four, because when we have a fraction, we divide. 8 divided by 2 equals four. Next:
4/4 is equal to 1 because 4 divided by 4 is one. 4 goes into 4 once. Next, we have:
That's because 6/3 = 2.
Hope this helps!
Question 4- is 32.25
question 5- is 12.4
question 6 -is 14/17
question 7 - is 10.7
Answer:
i dont know
Step-by-step explanation:sorry