The first and last one are similar
Answer:
B
Step-by-step explanation:
![6^{\frac{1}{4} } b^{\frac{3}{4} }c^{\frac{1}{4} }\\\\=(6^1b^3c^1)^{\frac{1}{4} }\\\\=(6b^3c)^\frac{1}{4} \\\\=\sqrt[4]{6b^3c}](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20b%5E%7B%5Cfrac%7B3%7D%7B4%7D%20%7Dc%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286%5E1b%5E3c%5E1%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%5C%5C%5C%5C%3D%286b%5E3c%29%5E%5Cfrac%7B1%7D%7B4%7D%20%5C%5C%5C%5C%3D%5Csqrt%5B4%5D%7B6b%5E3c%7D)
so answer is B
Hi there,
Take y from first equation and use it / substitute it into the second equation:
-2x + 8 = x - 1, so 3x = 9, therefore x = 3.
Then y = x - 1 = 3 - 1 => y = 2.
Solution is (3,2).
A quick check: 2 = -2*3 + 8, true, and 3 = 2 - 1, also true.
Green eyes.
Answer:
Exact Form:
9/4
Decimal Form:
2.25
Mixed Number Form:
2 1/4
Step-by-step explanation: