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olga nikolaevna [1]
3 years ago
12

Multiply 42 by the sum of 4 and r. I need help on number 10 please.

Mathematics
1 answer:
KIM [24]3 years ago
5 0

Answer:

42(4 + r) is the answer if I'm reading that correctly.

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Help please. You don’t have to explain it
muminat

Answer:

1st square =0

2nd square =1

3 0
3 years ago
Fill in each blank so that the resulting statements are true.The vertices of The foci are located at ____.
stealth61 [152]

Given equation is

\frac{x^2}{9}-\frac{y^2}{16}=1

It can be written as follows.

\frac{x^2}{3^2}-\frac{y^2}{4^2}=1

Which is of the form

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

where a=3 and b=4.

We know that the coordinates of the vertices are (a,0) and (-a,0)

Substitute a=3, we get

The vertices are (3,0) and (-3,0).

We know that the coordinates of the foci are (c,0) and (-c,0)

c=\sqrt[]{a^2+b^2}

Substitute a=3 and b=4, we get

c=\sqrt[]{3^2+4^2}=\sqrt[]{9+16}=\sqrt[]{25}=5

Substitute c=5, we get

Hence the foci are (5,0) and (-5,0).

5 0
1 year ago
Use the formula to approximate the speed of light, given that the energy contained in a 1kg object is 9 X 10^16 J
erica [24]

Answer:

c = 3\times 10^{8}\ m/s

Step-by-step explanation:

According to the theory of mass-energy equivalence:-

Energy=mass\times c^2

Where, c is the speed of the light

Given that, Mass = 1 kg

Energy = 9\times 10^{16}\ J

So, applying in the above equation as:-

Energy=mass\times c^2

9\times 10^{16}\ J=1\ kg\times c^2

Solving, we get that:-

c = 3\times 10^{8}\ m/s

4 0
3 years ago
If we have 28 ft of ribbon and one bow uses<br> 1.4 ft, how many bows can we make?
deff fn [24]

Answer: 20 bows

Step-by-step explanation:

28 divided by 1.4 =20

8 0
4 years ago
Read 2 more answers
Plz help plz no links
Bas_tet [7]

Answer:

-4.2, -3.5, -2.1, -1.5, -1, -0.5, 0.5, 3.5, 4.8 (least to greatest)

Step-by-step explanation:

7 0
3 years ago
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