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Inessa [10]
3 years ago
13

The teacher asked the students to design an experiment that would demonstrate that temperature will affect the pressure of a gas

. Which of the
following would be a valid experiment that shows the correct relationship between gas temperature and pressure?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0
Hikereee be your right thing lol just wants you in your house and your family that i please do that and i’m
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Along with removing drugs from the body, the kidneys also __________. A. balance pH levels B. release hormones that regulate blo
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Changes in the appearance of emission and absorption spectrums are caused by the activities of a. Protons b.electrons c.neutrons
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Changes in the appearance of emission and absorption spectrums are caused by the activities of electrons.

When you transmit an amount of light on atoms, the state of the energy of electrons will become higher. Why? Because it is absorbing the light's energy. Not all wavelengths will be absorbed by the atoms, only selective.

I hope that the explanation is enough to prove that it is the correct answer. Have a nice day!
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Select the correct pronoun.
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Calculate the pH of a buffer solution created by reacting 100 mL of 0.1 M NH3 with 90 mL of 0.1 M HNO3. (Remember, you can find
algol13

This question is asking for the pH of a buffer solution between ammonia and nitric acid, with given volumes and concentrations. At the end, the result turns out to be 10.488.

<h3>Buffers</h3>

In chemistry, buffers are known as substances attempting to hold a relatively constant pH by mixing and acid and a base (weak and strong). In such a way, for the substances given, the first step will be to calculate the consumed moles as they are mixed:

n_{NH_3}=0.1L*0.1mol/L=0.01mol\\\\n_{HNO_3}=0.09L*0.1mol/L=0.009mol

Now, since ammonia is in a greater proportion, one can calculate how much of it is left after being consumed by the nitric acid:

n_{NH_3}^{left}=0.01mol-0.009mol=0.001mol

And its new concentration:

[NH_3]=\frac{0.001mol}{0.1L+0.09L} =0.00526M

Next, with ammonia's ionization:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We set up the equilibrium expression based on ammonia's Kb:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]}

Which can be solved by introducing x and using ammonia's Kb:

1.8x10^{-5}=\frac{x^2}{0.00526M}\\ \\

Then, we solve for x which is also equal to the concentration of ammonium and hydroxide ions in the solution:

x=\sqrt{0.00526*1.8x10^{-5}}=0.000308M

Ultimately, we calculate the pOH and then turn it into pH with:

pOH=-log(0.00308)=3.512\\\\pH=14-3.512=10.488

Learn more about buffers: brainly.com/question/24188850

6 0
2 years ago
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