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3 years ago

Is the following relation a function?

Mathematics

1 answer:

Margarita [4]3 years ago

4 0

Answer:

Step-by-step explanation:

Because the value of domain is repeat

Like (0,1) and (0,3)

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The slope of the graph of the y=2x-2 is 2. What is the y-intercept?

oee [108]

The y-intercept is located at -2. In the formula y=mx+b, b is the y intercept.

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4 years ago

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Use the distributive property to find the product of 9 and 23.

Aleks04 [339]

9 x 23 = 207 So the answer is D. product means the answer of a multiplication question. The associative property states that you can add or multiply regardless of how the numbers are grouped. By 'grouped' we mean 'how you use parenthesis'. In other words, if you are adding or multiplying it does not matter where you put the parenthesis

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3 years ago

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Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable

bekas [8.4K]

Answer:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

$u=\frac{y}{x}$

Multiply both sides by x:

$ux=y$

Second step: Differentiate the substitution:

$u'x+u=y'$

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

$u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}$

$u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}$

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of $x^2$ so I'm going to divide top and bottom by $x^2$ :

$u'x+u=\frac{u+u^2}{3+u^2}$

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

$u'x=\frac{u+u^2}{3+u^2}-u$

Find a common denominator: Multiply second term on right hand side by $\frac{3+u^2}{3+u^2}$ :

$u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}$

Combine fractions while also distributing u to terms in ( ):

$u'x=\frac{u+u^2-3u-u^3}{3+u^2}$

$u'x=\frac{-u^3+u^2-2u}{3+u^2}$

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

$u' \frac{3+u^2}{-u^3+u^2-2u}x=1$

Divide both sides by x:

$\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}$

Reorder the top a little of left hand side using the commutative property for addition:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0

3 years ago

Alana has 2 1/4 bags of chocolate chips that she wants to use in 3 batches of chocolate chip cookies. How much of the chocolate

drek231 [11]

Answer:

1 1/3 bags of chocolate chips

Step-by-step explanation:

If Alana has 2 1/4 bags of chocolate chips that she wants to use in 3 batches of chocolate chip cookies, then we can say;

2 1/4 bags of cookies = 3 batches of chips

To determine how much of the chocolate chips will she use in each batch of cookies, we can say;

1 bag of cookies = x batches of chips

Equating both expressions

2 1/4 bags of cookies = 3 batches of chips

1 bag of cookies = x batches of chips

Cross multiply

2 1/4 x = 3

9/4 x = 3

9x/4 = 3

9x = 12

x = 12/9

x = 4/3

x = 1 1/3

Hence Alana will need 1 1/3 bags of chocolate chips

8 0

3 years ago

Plzzzzzzzz help for a brainly

ale4655 [162]

It is an isosceles triangle.

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3 years ago