To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Step-by-step explanation:
The number of cups of red paint is always 15 of the total number of cups. 0.2 of the total number of cups.
She writes the equation r = 15t (r = 0.2t) to describe the relationship.
In this case, the total no. of cups is an independent variable. No. of cups do not depend on any term.
The number of cups of red paint is a dependent variable as it depends on the number of cups.
The sample space is:
(1, 1); (1, 2) - sum of 3; (1, 3); (1, 4); (1, 5) - sum of 6; (1, 6);
(2, 1) - sum of 3; (2, 2); (2, 3); (2, 4) - sum of 6; (2, 5); (2, 6);
(3, 1); (3, 2); (3, 3) - sum of 6; (3, 4); (3, 5); (3, 6) - sum of 9;
(4, 1); (4, 2) - sum of 6; (4, 3); (4, 4); (4, 5) - sum of 9; (4, 6);
(5, 1) - sum of 6; (5, 2); (5, 3); (5, 4) - sum of 9; (5, 5); (5, 6);
(6, 1): (6, 2); (6, 3) - sum of 9; (6, 4); (6, 5); (6, 6)
My answer would probably be 10 because draw a line between the equal sign and the opposite of + is subtract and put it by the 17 so x=10
4(x - 3) - r + 2x = 5(3x - 7) - 9x
4x - 12 - r + 2x = 15x - 35 - 9x
6x - 12 - r = 6x - 35
6x - 6x - 12 + 35 = r
23 = r <==
with ur answer : -r = -23....u would multiply both sides by -1 to make r positive....resulting in : r = 23....so u basically got the same thing I did...just didn't quite finish
