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zalisa [80]
3 years ago
6

40% Of Francine's t shirts are red. If she has 20 shirts. How many are red

Mathematics
1 answer:
tester [92]3 years ago
3 0
The number of red t shirts is 8.
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Whats 85 divided by 1500 rounded but like done already​
Yuri [45]

Answer is 17.647 or if rounded 18

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4 years ago
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A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll
Mademuasel [1]

Amount of money collected in the 2-day fundraiser is represented by the following equations:

  • 12x + 4y = 152 .................. (i)
  • 32x + 12y = 420 .................. (ii)

where x is the cost of a chicken lunch and y is the cost of a vegetarian lunch

Multiplying (i) with 3 and subtracting it from (ii)

36x + 12y - (32x + 12y) = 456 - 420

⇒ 4x = 36

⇒ x = 9

Put value of x in (i)

⇒ 12 × 9 + 4y = 152

⇒ 108 + 4y = 152

⇒ 4y = 44

⇒ y = 11

Hence, cost of the vegetarian meal is 11.

7 0
3 years ago
is it always,sometimes, or never true that a scatter plot that shows a positive association suggest that the relationship is pro
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If there is a linear correlation between the two variables, the relation is then a direct proportionality (with slope positive or negative).

Hence, it is always true that <span>a scatter plot that shows a positive association suggests that the relationship is proportional.</span>
6 0
3 years ago
Forty tickets are sold for a raffle with two prizes. You buy two tickets. What is the probability that you will win both prizes?
Trava [24]
Well, the first one is 2/40=1/20. The 2nd one is 1/39. You multiply these to get 1/780.
5 0
3 years ago
You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w
Margaret [11]

Answer:

a

  The null hypothesis is  

         H_o  : \mu  =  21

The Alternative  hypothesis is  

           H_a  :  \mu<   21

b

     \sigma_{\= x} =   0.8944

c

   t = -2.236

d

  Yes the  mean population is  significantly less than 21.

Step-by-step explanation:

From the question we are given

           a set of  data  

                               20  18  17  22  18

       The confidence level is 90%

       The  sample  size  is  n =  5  

Generally the mean of the sample  is  mathematically evaluated as

        \= x  =  \frac{20 + 18 +  17 +  22 +  18}{5}

       \= x  =  19

The standard deviation is evaluated as

        \sigma =  \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }

         \sigma =  \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }

         \sigma = 2

Now the confidence level is given as  90 %  hence the level of significance can be evaluated as

         \alpha = 100 - 90

        \alpha = 10%

         \alpha =0.10

Now the null hypothesis is  

         H_o  : \mu  =  21

the Alternative  hypothesis is  

           H_a  :  \mu<   21

The  standard error of mean is mathematically evaluated as

         \sigma_{\= x} =   \frac{\sigma}{ \sqrt{n} }

substituting values

         \sigma_{\= x} =   \frac{2}{ \sqrt{5 } }

        \sigma_{\= x} =   0.8944

The test statistic is  evaluated as  

              t =  \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }

substituting values

              t =  \frac{ 19  - 21 }{ 0.8944 }

              t = -2.236

The  critical value of the level of significance is  obtained from the critical value table for z values as  

                   z_{0.10} =  1.28

Looking at the obtained value we see that z_{0.10} is greater than the test statistics value so the null hypothesis is rejected

6 0
3 years ago
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