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2 years ago

Module 2 - Lesson 23 9152/29 ANSWER IT FAST PLEASE

Mathematics

1 answer:

Vanyuwa [196]2 years ago

8 0

Answer:

will

Step-by-step explanation:

have

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Factorise the expression: am^2 + bm^2 + bn^2+an^2

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Answer:

( a+b) ( m^2 + n^2)

Step-by-step explanation:

factorise like terms

m^2 ( a + b ) + n^2 ( m^2 + n^2)

then put like terms together put remaining terms in a bracket

( a + b) ( m^2 + n^2 )

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1 year ago

HELP ASAP HELP PLEASE ASAP

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No no no no no no no no no

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2 years ago

Enter the degree form for 3π/4 radians in the box.

Paraphin [41]

Answer:

135 degrees

Step-by-step explanation:

2π radians is the central angle of a full circle, so 2π radians is 360 degrees.

That means that π radians = 180 degrees.

3π/4 radians * (180 degrees)/(π radians) = 135 degrees

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2 years ago

In the diagram, a circle centered at the origin, a right triangle, and the Pythagorean theorem are used to derive the equation o

ehidna [41]

Answer:

(x – h)2 + (y – k)2 = r2

Step-by-step explanation:

If the center of the circle were moved from the origin to the point (h, k) and point P at (x, y) remains on the edge of the circle the equation of the new circle

(x – h)2 + (y – k)2 = r2

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2 years ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete the st

Zina [86]

Question:

If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.

Answer:

$Sin\theta = \frac{-15}{17}$

$Tan\theta = \frac{15}{8}$

Step-by-step explanation:

Given

cos(θ) =-8/17

Required

sin(θ) = __

tan(θ) =__

The first step is to determine the length of the third side

Given that

$cos(\theta) = \frac{Adj}{Hyp}$

Where Adj and Hyp represent Adjacent and Hypotenuse

$cos(\theta) = \frac{-8}{17}$

By comparison

$Adj = -8\ and\ Hyp = 17$

Using Pythagoras

$Hyp^2 = Adj^2 + Opp^2$

By Substitution

$17^2 = (-8)^2 + Opp^2$

$289 = 64 + Opp^2$

Subtract 64 from both sides

$289 - 64 = 64 - 64 + Opp^2$

$225 = Opp^2$

Take square roots of both sides

$\sqrt{225} = \sqrt{Opp^2}$

$\sqrt{225} = Opp$

$15 = Opp$

$Opp = 15$

The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

$Opp = -15$

From trigonometry

$Sin\theta = \frac{Opp}{Hyp}$

$Sin\theta = \frac{-15}{17}$

Also from trigonometry

$Tan\theta = Sin\theta / Cos\theta$

$Tan\theta = \frac{-15}{17} / \frac{-8}{17}$

$Tan\theta = \frac{-15}{17} * \frac{-17}{8}$

$Tan\theta = \frac{-15 * -17}{17 * 8}$

$Tan\theta = \frac{15 * 17}{17 * 8}$

$Tan\theta = \frac{15}{8}$

5 0

2 years ago