What is 88.6 rounded to the nearest whole number?

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

Answer:

Step-by-step explanation:

This is how to round 88.6 to the nearest whole number. In other words, this is how to round 88.6 to the nearest integer. 88.6 has two parts. The integer part to the left of the decimal point and the fractional part to the right of the decimal point: Integer Part: 88 Fractional Part: 60 Our goal is to round it so we only have an integer part using the following rules: If the first digit in the fractional part of 88.6 is less than 5 then we simply remove the fractional part to get the answer. If the first digit in the fractional part of 88.6 is 5 or above, then we add 1 to the integer part and remove the fractional part to get the answer. The first digit in the fractional part is 6 and 6 is 5 or above. Therefore, we add 1 to the integer part and remove the fractional part to get 88.6 rounded to the nearest whole number as: 89

kicyunya [14]3 years ago

8 0

Answer: 89

Step-by-step explanation:

If a decimal is being rounded to the nearest whole number then we are trying to eliminate the decimal. If the tenths value in the number is equal to or greater than 5, then you will make the ones digit go up by one.

88.6 the tenth digit is 6 and it is greater than 5 so you will make the ones digit go up by one more. The ones digit is 8 so you will get 9.

The number will then be 89

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Which expression is equivalent to...? Screenshots attached. Please help! Thank you.

Studentka2010 [4]

Answer:

$4x^{3} y^{2} (\sqrt[3]{4 x y})$

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

$\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }$

Then we'll extract the 4 from the cubic root. We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

$\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }$

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

$4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }$