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algol13
3 years ago
8

Please explain asap :(

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Answer:

x = 40

Step-by-step explanation:

Both angles are opposites and will therefore have the same measurements.

Set your formula up as

142 = 3x + 22

142 - 22 = 3x

120 = 3x

120/3 = x

40 = x

You can also test this by placing 40 in place of x in your formula to check your work

3 * 40 + 22 = 142

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Solve for x 9 ( x + 1 ) = 25 + x
ELEN [110]

Answer: x=2

Step-by-step explanation:

Given

9(x+1)=25+x

Distributive property

9x+9=25+x

Subtract x on both sides

9x+9-x=25+x-x

8x+9=25

Subtract 9 on both sides

8x+9-9=25-9

8x=16

Divide 8 on both sides

8/8 x=16/8

x=2

Hope this helps!! :)

Please let me know if you have any question

6 0
3 years ago
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Dennis_Churaev [7]

Answer:

Sorry, it's actually the third one, 4.8 feet

Step-by-step explanation:

First, you divide the length of the family room tv by the length of the tv in Louise's room

5 divided by 1.5 equals 3.33

Then, you divide the width of the family room tv to get the width of Louise's tv

3 divided by 3.33 is 0.9

Now, you follow the formula for perimeter.

(0.9 + 1.5) x 2 = 4.8

The perimeter of Louise's tv is 4.8 feet.

7 0
4 years ago
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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra
Rainbow [258]

Answer:

x = t

y = 1 - t

z = 2t

Step-by-step explanation:

Given

x=t

y=e^{-t}

z=2t-t^2

(0, 1, 0)

The vector equation is given as:

r(t) = (x,y,z)

Substitute values for x, y and z

r(t) = (t,\ e^{-t},\ 2t - t^2)

Differentiate:

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

The parametric value that corresponds to (0, 1, 0) is:

t = 0

Substitute 0 for t in r'(t)

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

r'(0) = (1,\ -e^{-0},\ 2 - 2*0)

r'(0) = (1,\ -1,\ 2 - 0)

r'(0) = (1,\ -1,\ 2)

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

r(t) = a + tv

Such that:

a = (0,1,0) and v = r'(0) = (1,-1,2)

The equation becomes:

r(t) = (0,1,0) + t(1,-1,2)

r(t) = (0,1,0) + (t,-t,2t)

r(t) = (0+t,1-t,0+2t)

r(t) = (t,1-t,2t)

By comparison:

r(t) = (x,y,z) and r(t) = (t,1-t,2t)

The parametric equations for the tangent line are:

x = t

y = 1 - t

z = 2t

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3 years ago
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