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Licemer1 [7]
3 years ago
6

Need help asap!! Tysmm

Mathematics
2 answers:
Levart [38]3 years ago
8 0

Answer:

1) 9x-4

Step-by-step explanation:

7x+2x= 9x

-8+4= -4

9x-4

DIA [1.3K]3 years ago
4 0
2x+7x= 9x
-8+4=-4
9x-4
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Solve the system of linear equations. <br> −8x+5y=26<br> 9x−3y=−3
Sloan [31]

Answer: x = 3 and y = 10

Step-by-step explanation:

-8x + 5y = 26     .................. equation 1

9x - 3y = -3          ................ equation 2

Solving the system of linear equations by elimination method.

The means we have to make the coefficient of one of the variable the same in order to eliminate the variable first.

Let us eliminate the variable y first , this means we will multiply equation 1 by 3 and multiply equation 2 by 5. Doing this , we have

-24x + 15y = 78      ............. equation 3

45x - 15y = -15     ................ equation 4

Now that we have the same coefficient , we have to check their signs , if the have the same signs , we will subtract , that is , if both are having positive signs , we will subtract , if both have negative signs , we will also subtract but if their signs differ we will add. Following this rule and considering the equations above , the coefficients of y have different signs , so we will add equation 3 and equation 4 , so we have:

21x = 63

x = 63/21

x = 3

Substitute x = 3 into equation 1 or equation 2 to get the value of y , using equation 2 , we have

9x - 3y = -3

9(3) - 3y = -3

27 - 3y = -3

27+3 = 3y

30 = 3y

30/3 = y

Therefore y = 10

Therefore : x = 3 and y = 10

8 0
4 years ago
Which two features are present in a plant cell but not in an animal cell
RoseWind [281]

Answer:

The two features present in a plant cell, but not in an animal cell are chloroplasts and a large central vacuole.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The probability that a visitor to an animal shelter will adopt a dog is .20. out of nine visits, what is the probability that at
lana66690 [7]
This is a binomial probability situation, since a dog either is adopted or is not adopted.  The chances of a dog's being adopted in 0.20.  Here we're speaking of 9 visits.  Thus, n=9, p=0.20.

One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs.  Add together these nine probabilities to get your answer.

But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.

Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134.  Subtracting this from 1.000, we get 0.866 (answer to this problem).
8 0
3 years ago
12=15(z-1/5) does anybody know how to solve this
Fittoniya [83]

Answer:

-15

Step-by-step explanation:

5 0
3 years ago
In 1980, the average cost of a pack of cigarettes was $0.88. In 2000, the average cost was $5.31 per pack.
yan [13]

Answer:

The average rate of change of the cost of a pack is 22 cents per year.

Another name for the average <em>rate of change</em> is <em>slope</em>.

Step-by-step explanation:

The average rate of change of the cost of a pack (r), in monetary units per year, is equal to the change in the average cost of a pack (\Delta c), in monetary units, divided by the change in time (\Delta t), in years. Then, the average rate of change is:

r = \frac{\$\,5.31-\$\,0.88}{2000-1980}

r = \$\,0.22\,\frac{1}{yr}

The average rate of change of the cost of a pack is 22 cents per year.

Another name for the average <em>rate of change</em> is <em>slope</em>.

8 0
3 years ago
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