PLS HELP I WILL GIVE BRAINLIEST

3n^2=6-17n I need Vertex form please.

nasty-shy [4]

Answer:

3( n + $\frac{17}{6}$ )² - $\frac{361}{12}$ = 0

Step-by-step explanation:

3n² = 6 - 17n ⇔ 3n² + 17n - 6 = 0

3( n² + 2 × $\frac{17}{6}$ n + ( $\frac{17}{6}$ )² - ( $\frac{17}{6}$ )² - 2 ) = 0

3( n + $\frac{17}{6}$ )² - 3 × $\frac{289}{36}$ - 6 = 0

3( n + $\frac{17}{6}$ )² - $\frac{361}{12}$ = 0

8 0

3 years ago

The amount y of your friend's allowance if the amount she receives is $77 more than the amount x you receive.

sergeinik [125]

The amount y is equals to x+77

8 0

3 years ago

Which situation could be represented by an exponential function select each correct answer

ANTONII [103]

Answer:

The first and third options are the examples of exponential functions.

Step-by-step explanation:

When a quantity is compounded after a certain interval of time at a certain rate, then we can assume that the situation can be represented by an exponential function.

In the first option: An event organizer finds each year's attendance for the past five years is about $\frac{4}{5}$ of previous year's attendance.

So, here the total attendance is compounding every year by a factor $\frac{4}{5}$ of previous year's attendance.

Again, in the third case: The total population is increasing by about 7.5% each year.

Hence, the population is compounded every year by 7.5% of the previous year's population.

Therefore, the first and third options are examples of exponential functions. (Answer)

3 0

3 years ago

Evaluate the Expression B^2-4 ac given by that a = -2 ,, b= -2 and c =2

Lapatulllka [165]

F* you B*!!!!!! Your so S*! That's the easiest thing in the world!!

4 0

4 years ago

100 points! Mhanifa can you please help? Look at the picture attached. I will mark brainliest!

dimulka [17.4K]

Answer:

1 and 2.

Midpoints calculated, plotted and connected to make the triangle DEF, see the attached.

D= (-2, 2), E = (-1, -2), F = (-4, -1)

3.

As per definition, midsegment is parallel to a side.

Parallel lines have same slope.

Find slopes of FD and CB and compare.

m(FD) = (2 - (-1))/(-2 -(-4)) = 3/2
m(CB) = (1 - (-5))/(1 - (-3)) = 6/4 = 3/2
As we see the slopes are same

Find the slopes of FE and AB and compare.

m(FE) = (-2 - (- 1))/(-1 - (-4)) = -1/3
m(AB) = (1 - 3)/(1 - (-5)) = -2/6 = -1/3
Slopes are same

Find the slopes of DE and AC and compare.

m(DE) = (-2 - 2)/(-1 - (-2)) = -4/1 = -4
m(AC) = (-5 - 3)/(-3 - (-5)) = -8/2 = -4
Slopes are same

4.

As per definition, midsegment is half the parallel side.

We'll show that FD = 1/2CB

FD = $\sqrt{(2+1)^2+(-2+4)^2}$ = $\sqrt{3^2+2^2}$ = $\sqrt{13}$
CB = $\sqrt{(1 + 5)^2+(1+3)^2}$ = $\sqrt{6^2+4^2}$ = 2 $\sqrt{13}$
As we see FD = 1/2CB

FE = 1/2AB

FE = $\sqrt{(-4+1)^2+(-1+2)^2}$ = $\sqrt{3^2+1^2}$ = $\sqrt{10}$
AB = $\sqrt{(-5 -1)^2+(3-1)^2}$ = $\sqrt{6^2+2^2}$ = 2 $\sqrt{10}$
As we see FE = 1/2AB

DE = 1/2AC

DE = $\sqrt{(-2+1)^2+(2+2)^2}$ = $\sqrt{1^2+4^2}$ = $\sqrt{17}$
AC = $\sqrt{(-5 +3)^2+(3+5)^2}$ = $\sqrt{2^2+8^2}$ = 2 $\sqrt{17}$
As we see DE = 1/2AC

3 0

3 years ago

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