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kifflom [539]
3 years ago
7

PLS HELP I WILL GIVE BRAINLIEST

Mathematics
1 answer:
pogonyaev3 years ago
8 0

Answer:

Part A: A. 28+5h

Part B: Yes

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radius which is the center point of a circle

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Circle O has a circumference of approximately 44 in.
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22

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Given that f(3)=9,f′(3)=3,g(9)=3, and g′(9)=5, what is the approximate value of g(f(3.02))?
Sati [7]
F(3) = 9
f'(3) = 3
L(x) = linear approximation to f(x) at x = a
L(x) = linear approximation to f(x) at x = 3
L(x) = f'(a)*(x-a)+f(a)
L(x) = f'(3)*(x-3)+f(3)
L(x) = 3*(x-3)+9
L(x) = 3x-9+9
L(x) = 3x
L(3.02) = 3*3.02
L(3.02) = 9.06
So f(3.02) is approximately 9.06 based on the L(x) linear approximation

g(9) = 3
g'(9) = 5
M(x) = linear approximation to g(x) at x = 9
M(x) = linear approximation to g(x) at x = a
M(x) = g'(a)*(x-a)+g(a)
M(x) = g'(9)*(x-9)+g(9)
M(x) = 5*(x-9)+3
M(x) = 5x-45+3
M(x) = 5x-42
M(9.06) = 5*9.06-42
M(9.06) = 3.3

So g(9.06) is approximately equal to 3.3 based on the linear approximation M(x)

In summary, this means
g(9.06) = g(f(3.02)) = 3.3
which are approximations

The final answer is 3.3
8 0
4 years ago
From the set {0, 1, 15}, use substitution to determine which value of makes the equation true.
DanielleElmas [232]

Answer:

b = 0.

Step-by-step explanation:

The only value for b that makes the equation true is 0. So, the equation has a unique solution of b = 0.

6 0
2 years ago
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