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grigory [225]
3 years ago
6

Is 5 a factor of 35 56 51 40

Mathematics
2 answers:
tester [92]3 years ago
6 0
5 is factor of 35 and 40 not 56 and 51
FromTheMoon [43]3 years ago
3 0
5 is a factor of 35 and 40 but not 56 and 51. Factors of 5 always end in either 0 or 5.
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Calculeaza a-b+c stiind ca a-1538=b+718=2000-c=1074
snow_tiger [21]
A-1538=1074
a=1538+1074
a=2612




b+718=1074
b=1074-718
b=356



2000-c=1074
c=2000-1074
c=926


2612-356+926=3182
8 0
3 years ago
Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

3 0
3 years ago
Help me fill this out thanks
alukav5142 [94]

Answer:

This is an isosceles right triangle, then we have

2 x u^2 = [6sqrt(2)]^2

<=> 2 x u^2 = 72

<=> u^2 = 36

<=> u = 6

Hope this helps!

:)

8 0
4 years ago
Amir stands on a balcony and throws a ball to his dog, who is at ground level.
Bumek [7]

Answer:

16 meters

Step-by-step explanation:

The height function is given by:

h(x)=-(x+1)(x-7)\\h(x)=-(x^2+x-7x-7)\\h(x)=-x^2+6x+7

The value of x, in seconds, for which the derivate of the height function is zero, is the time at which the maximum height occurs:

\frac{dh(x)}{dx}= h'(x)=-2x+6=0\\x=3

For x = 3 seconds, the height is:

h(3)=-(3^2)+6*3+7\\h(3)=16\ m

The maximum height that the ball will reach is 16 meters.

6 0
3 years ago
Read 2 more answers
If there is a 10% chance of sun tomorrow and a 20% chance of wind and no sun, what is the probability that it is windy, given th
professor190 [17]
Since there are two events happening simultaneously (windy and no sun), we can apply the concept of conditional probability here. P(A|B) = P(A∩B)/P(B) where it means that given B is happening, the probability that A is happening as well is the ratio of the chance for A and B to happen simultaneously over the chance of B to happen. For our case, this can be interpreted as P(A|B): it is the probability that it is windy (A) GIVEN that there is no sun (B) P(A∩B) : chance of wind and no sun P(B) : chance that there is no sun tomorrow The chance of P(A∩B) is already given as 20% or 0.20. Since there is 10% or 0.10 chance of sun, then chances of having no sun tomorrow is (1-0.10) = 0.90. Thus, we have P(A|B) = 0.2/0.9 ≈ 0.22 or 22%. So, answer is B: 22%<span>.</span>
5 0
3 years ago
Read 2 more answers
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