Answer:
the side of a square is 45 m
Step-by-step explanation:
The computation of the side of the square field that contains the similar area as compared with rhombus is given below:
As we know that
Area of rhombus = Base × Altitude
= 81 × 25
= 2025
And, area of Square = Side × side
2025 = side^2
side = √2025
= 45m
Hence, the side of a square is 45 m
Question is not complete, so i have attached it.
Answer:
B: -2x² - 6x² - 6x + 3x + 3 + 2
Step-by-step explanation:
From the image attached, the given polynomial is;
3 - 6x - 2x² + 3x - 6x² + 2
For like terms to be next to each other, we have to rearrange it as follows;
-2x² - 6x² - 6x + 3x + 3 + 2
Like terms are x² and x, thus they are now arranged next to each other.
The only option that corresponds to our answer is option B
Let the two numbers be x and y
Then
x + y = 60
And
x - y = 2
x = y + 2
Putting the value of x in the first equation we get
x + y = 60
y + 2 + y= 60
2y + 2 = 60
2y = 60 - 2
2y = 58
y = 58/2
y = 29
Now putting the value of y in the first equation we get
x + y = 60
x + 29 = 60
x = 60 - 29
x = 31
So the value of the two numbers comes out to be 31 and 29. I hope the procedure is clear enough for you to understand.
Answer:
Total amount of fencing needed as an algebraic expression in terms of x is: <em>10x</em><em> </em><em>+</em><em> </em><em>3</em> .
Step-by-step explanation:
As it is given that each rectangle has the same dimensions, the dimensions of each rectangle must be: x units by 2x + 1 units.
Based on this, we can calculate the total amount of fencing needed.
Let width of each rectangle = x
Let length of each rectangle = 2x + 1
There are 4 widths and 3 lengths in total of fencing.
Therefore:
= 4 ( x ) + 3 ( 2x + 1 )
Expand:
= 4x + 6x + 3
Group like-terms:
= 10x + 3
Answer:
number 2.) 1,500g
Step-by-step explanation:
i just know..
