Can you evaluate the expressions for the given value. (show steps if you can)

Mathematics

1 answer:

exis [7]2 years ago

6 0

Answer:

Q1. -45

Q2. -10

Q3. 31?

Step-by-step explanation:

Q1 -- you times -8 and 2 which comes out to -16. Since you have -16 + 1 inside of the parentheses you add 1 to -16 which comes out to -15. Then you take -15 times 3 and it comes out to -45.

Q2 -- the m gets replaced by the 5 so now its -2 times 5. Which comes out to -10. Then you take -10 times 2, which is -20. Now take -20 + 10 which gives us the answer of -10.

Q3 -- I'm not completely sure on this one but I think the equation would transfer to this 2*5 + 5*3 + 2*3. So 2*5 is 10, 5*3 is 15, and 2*3 is 6. Add them all together and you get 31.

I hope this was right and it helps you!

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Fill in Sin, Cos, and tan ratio for angle x. Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .