3 years ago

the radius of a cylindrical construction pipe is 2 ft. If the pipe is 26 ft long, what is its volume?

2 answers:

posledela3 years ago

7 0

Answer:

V=326.725636 or V=104 $\pi$

Step-by-step explanation:

V= $\pi$ $r^{2}$ h

V= $\pi$ $2^{2}$ (26)

V= $\pi$ 4(26)

V=326.725636

6 0

Thxr2x26=

3.14x2x2x26= 326.56 ft3

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