Answer:
It is one-half the area of a rectangle with sides 4 units × 3 units
Step-by-step explanation:
One side of the triangle is on the line y = 2 between points x=2 and x=6. So, that side has length 6-2 = 4.
The opposite vertex has y-value 5, so is 3 units away from the line y = 2.
The area of the triangle can be considered to have a base of 4 and a height of 3. In the formula ...
A = (1/2)bh
we find the area to be ...
A = (1/2)×(4 units)×(3 units) . . . . triangle area
__
A rectangle's area is the product of its length and width. So, a rectangle that is 4 units by 3 units will have an area of ...
A = (4 units)×(3 units) . . . . rectangle area
Comparing the two area formulas, we see that the triangle area is 1/2 the area of the rectangle with sides 4 units × 3 units.
Answer: No Hope this helps, please consider making me Brainliest.
Step-by-step explanation:
If it is not proportional, it will not cross the origin (I remember this data from the other question you posted). Hope this helps, please consider making me Brainliest.
Total of angles in 180 so:
46+90+8x+4=180
8x=40
x=5
Answer:
f average = 1
smaller value c = 3
larger value c = 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
The first parabola has vertex (-1, 0) and y-intercept (0, 1).
We plug these values into the given vertex form equation of a parabola:
y - k = a(x - h)^2 becomes
y - 0 = a(x + 1)^2
Next, we subst. the coordinates of the y-intercept (0, 1) into the above, obtaining:
1 = a(0 + 1)^2, and from this we know that a = 1. Thus, the equation of the first parabola is
y = (x + 1)^2
Second parabola: We follow essentially the same approach. Identify the vertex and the two horizontal intercepts. They are:
vertex: (1, 4)
x-intercepts: (-1, 0) and (3, 0)
Subbing these values into y - k = a(x - h)^2, we obtain:
0 - 4 = a(3 - 1)^2, or
-4 = a(2)². This yields a = -1.
Then the desired equation of the parabola is
y - 4 = -(x - 1)^2
