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3 years ago

What is the value of 3 + x when x = 19?

Mathematics

1 answer:

zavuch27 [327]3 years ago

6 0

Answer:

Its 22

Step-by-step explanation:

x is 19

so 3+19 is 22

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Round to the nearest 10th if necessary

Lana71 [14]

Answer:

38.7°.

Step-by-step explanation:

from trigonometrical ratios

SO TO CA

H A H.

Tan°=opposite/adjacent.

Tan°=48/60

Tan°=0.8000

°= Tan-1(0.8000)

°=38.65°≈38.7°

6 0

2 years ago

Hello! Can someone help with this question?

IgorC [24]

Hello! :)

$\large\boxed{\text{70 seconds}}$

Use a proportion to find how many seconds are needed to fold 5 shirts.

We are given that he takes 28 seconds to fold 2 shirts:

28 sec : 2 shirts

We are not given the amount of time needed for 5 shirts, which we need to solve:

x seconds : 5 shirts

Express in a fraction:

$\frac{2 shirts}{28 seconds} = \frac{5 shirts}{xseconds}$

Cross multiply and simplify:

$2 * x = 5 * 28\\\\2x = 140\\\\x = 70 sec$

Therefore, he needs 70 seconds to fold 5 shirts.

5 0

3 years ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .