Well first we need to change the format of the equations to slope-intercept, or y=mx+b.
So the first one (x + y < 1) will be changed to y < -x + 1.
The second one (2y ≥ x - 4) will be changed to y <span>≥ x/2 - 2.
Now we can analyze each graph.
In every single graph the first equation (y < -x + 1) is graphed correctly.
Now for the second equation, we can see that only the first and last graph correctly format to the equation.
Now for the shading:
The first equation shows us that y is less than -x +1, making the shading go under the dotted line. (to the left)
The second equation shows us that y is greater than or equal to x/2 - 2, making the shading go above the line. (also to the left)
Therefore, when we shade, the overlapping shading is correctly formatted in the first graph.
Hope this helped, comment any questions you have for me.</span>
Answer:
the twelve pack
Step-by-step explanation:
12 pack = $10.08 if u get the 6 pack for $5.34 and want to buy two pack it equals $10.68 if you want to save change buy the 12 pack
Answer:
7/1 - 7/1 + 17/1 = 17
Step-by-step explanation:
Answer:
The maximum annual variable cost he can have to reach his projection is $1,940
Step-by-step explanation:
Given;
Number of miles drive per year N = 10,000 miles
Total annual Fixed cost F = $3,460
cost per mile(rate) r = $0.54 or less
Total cost = fixed cost + variable cost
Total cost = cost per mile × number of miles
Total cost = r × N = $0.54 × 10,000 = $5,400
Let V represent the total variable cost per year;
F + V ≤ r × N
Substituting the values;
3,460 + V ≤ 5,400
V ≤ 5,400 - 3,460
V ≤ 1,940
The maximum annual variable cost he can have to reach his projection is $1,940
Answer:
see explanation
Step-by-step explanation:
(a)
The angle on the circumference is half the central angle , that is
∠ A = ∠ BOC ÷ 2 = 50° ÷ 2 = 25°
(b)
Δ AOC is isosceles ( OA = OC , radii of the same circle ) then the base angles are congruent , that is
∠ ACO = ∠ A = 25°
(c)
Δ BOC is isosceles ( OB = OC, radii of the same circle ) then the base angles are congruent, that is
∠ BCO = 
= 
= 65°
(d)
∠ ACO + ∠ BCO = 25° + 65° = 90° ( angle in a semicircle )
