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nadya68 [22]
3 years ago
8

PLEASE I NEED TO PASS

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0

hi,,

329.1 is the answer...

if I round off the no. nearest whole no.

then the answer is 329.

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I need help on this, please hurry and thank you!
inna [77]

Answer:

A.\ a_n=n^2+1

Step-by-step explanation:

Check:

a_n=n^2+1\\\\a_1=1^2+1=1+1=2\qquad CORRECT\\\\a_2=2^2+1=4+1=5\qquad CORRECT\\\\a_3=3^2+1=9+1=10\qquad CORRECT\\\\a_4=4^2+1=16+1=17\qquad CORRECT\\\\a_5=5^2+1=25+1=26\qquad CORRECT

Used PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

First Power, next Addition

4 0
3 years ago
Read 2 more answers
Math is annoying! Can someone help me please?
lord [1]
16.  would be C since they both consist of the same variable to the same power

17. x-2x+7-9+4x
     c. 3x-2
18. -4(3a-5). You would multiply -4 by 3 a, and -4 by -5. It turns to
      -4(3a)-4(-5)
     a. -12a+20
4 0
3 years ago
Solve the equation.<br><br> −10x + 1 + 7x = 37
matrenka [14]
You combine like terms which are -10x and 7x and 1 and 37. Then it becomes -3x=36. x would equal to 36/-3, which is -12.
8 0
3 years ago
Read 2 more answers
Evaluate k(4) for the function k(x)=18−2x
KiRa [710]

Answer:

k(4) = 10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

k(x) = 18 - 2x

k(4) is x = 4

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    k(4) = 18 - 2(4)
  2. Multiply:                               k(4) = 18 - 8
  3. Subtract:                              k(4) = 10
5 0
3 years ago
5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls​
miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = cos^{2}x - sin^{2}x

2. Pythagorean identity:

cos^{2}x + sin^{2}x = 1

Back to your problem, replacing the variable by the above:

5cosx-sin\frac{x}{2}+7 = 0

5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0 By Double-angle formula

5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0 By Pythagorean identity

Given y = \frac{x}{2}

5(1-2sin^{2}y) - 2siny + 7 = 0

10sin^{2}y+2siny-12=0

5sin^{2}y+siny-6=0

(5siny + 6)(siny - 1)=0, we know -1 < sinx < 1, for every x ∈ R

siny = 1, y =90

y = \frac{x}{2}

x = 180

8 0
3 years ago
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