Which expression is a factor of x² − 5x − 6?

(I need to go to sleep please answer!)How many triangles can be constructed with angles measuring 25º, 25º, and 130º?

Burka [1]

There would be 3 triangles formed.
Each interior angle of a triangle will sum up to 180 degrees.

The 1st triangle will have 130,25, and 25 as its angle measures.

The angle 130 degrees will be divided into 2 to create 2 right triangle. Each triangle will have angle measurements of 25, 65, and 90 degrees.

8 0

3 years ago

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The flower shop has 40 times as many flowers in one cooler as Julia has in her bouquet. The cooler has 120 flowers. How many flo

kiruha [24]

The answer is 4,800 if u multiply 120x40

8 0

3 years ago

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You start driving north for 27 miles, turn right, and drive east for

WITCHER [35]

Answer:

Using the Pythagorean theorem

a^2 + b^2 = c^2

c = square root(a^2 + b^2)

c = square root(27^2 + 36^2)

c = square root(729 + 1296)

c = square root(2025)

c= 45

<u>Straight Line Distance = 45 miles</u>

6 0

3 years ago

At Garland School, 3/5 of the 490 students are boys.

Masja [62]

Step-by-step explanation:

the bowood school by 455 kids

5 0

3 years ago

The equation of a circle is given below. Identify the radius and center.

bonufazy [111]

Answer:

The center is (3,1) and the radius is 3.

Step-by-step explanation:

The goal is to write in $(x-h)^2+(y-k)^2=r^2$ because this tells us the center (h,k) and the radius r.

So we are going to need to complete the square 2 times here, once for x and the other time for y.

I'm going to use this formula to help me to complete the square:

$x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2$ .

So first step:

I'm going to group my x's together and my y's.

$x^2-6x+\text{ ___ }+y^2-2y+\text{ ___ }+1=0$

Second step:

I'm going to go ahead and subtract that one on both sides. Those blanks are there because I'm going to fill them in with a number so that I can write the x part and y part as a square. Remember whatever you add on one side you must add on the other. So I'm going to put 2 more blanks to fill in on the opposite side of the equation.

$x^2-6x+\text{ ___ }+y^2-2y+\text{ ___ }=-1+\text{ ___ }+\text{ ___}$

Third step:

Alright first blank I'm putting (-6/2)^2 due to my completing the square formula. That means this value will also go on the other side in on of those blanks.

In the second blank I'm going to put (-2/2)^2 due to the completing the square formula. This must also go on one of the blanks on the other side.

So we have:

$x^2-6x+(\frac{-6}{2})^2+y^2-2y+(\frac{-2}{2})^2=-1+(\frac{-6}{2})^2+(\frac{-2}{2})^2$