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3 years ago

) Al repartir laminas entre mis amigos, pude darle 5 a

Mathematics

1 answer:

prisoha [69]3 years ago

8 0

Answer:

Había cinco amigos al principio y siete laminas en total. (Using google translate)

Step-by-step explanation:

pude darle 5 a cada = 5 amigos

5 a cada uno y me sobran 2 amigos más, por lo que las repartí de nuevo y pude darle = siete laminas

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6y+4−3y−7=3(y−1) How many solutions are for this?

Kryger [21]

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

Order of Operations: BPEMDAS
Regular + Equality Properties

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Combine like terms: 3y - 3 = 3(y - 1)
Distribute 3: 3y - 3 = 3y - 3
Subtract 3y on both sides: -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number y and it will render the equation true.

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2 years ago

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A dog weighs 35.4 kilograms.1 kilogram=2.2 pounds,1 pound=0.45 kilograms.About how much does the dog weigh in pounds?Round to ne

AlladinOne [14]

Answer: 78 pounds
Explanation: if 1 kilogram is 2.2 pounds, just multiply the weight in kg by 2.2:
35.4 x 2.2 = 77.88
Round to nearest whole: 78.
So the dog is 78 pounds

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2 years ago

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What is the value of c so that 9x^2 + 15x + c = 0 has one rational solution

valentinak56 [21]

Answer:

c=-9x^2-15x

Step-by-step explanation:

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Find the two correct values of x in the equation 3x² = y when y = 75.

valentina_108 [34]

Answer:

5 and -5

Step-by-step explanation:

3x² = 75

x² = 75/3

x² = √25

x = 5 and - 5

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2 years ago

Y is directly proportional to square root of x If y=56 when x=49 find, y when x=81

STALIN [3.7K]

$\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{\begin{array}{llll} \textit{"y" directly}\\ \textit{proportional to }\sqrt{x} \end{array}}{y = k\sqrt{x}}\qquad \textit{we know that} \begin{cases} y = 56\\ x = 49 \end{cases}\implies 56=k\sqrt{49} \\\\\\ 56=7k\implies \cfrac{56}{7}=k\implies 8=k~\hfill \boxed{y=8\sqrt{x}} \\\\\\ \textit{when x = 81, what is "y"?}\hfill y=8\sqrt{81}\implies y=8(9)\implies y=72$

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2 years ago