Answer:
scale factor of the smaller prism to the larger prism is B. 21/23
Step-by-step explanation:
Given
surface areas of two similar hexagonal prisms are 882cm² and 1,058 cm²?
scale factor is ratio of sides of two similar objects
thus scale factor for given prism will be = side of smaller prism / side of larger prism
in general rule
If shape of solid has scale factor of k
scale factor of area = k²
scale factor of volume = k³
_____________________________
Given in the problem area of two prism is given
we know area = side^2
scale factor of area = k²
k^2 = area of smaller prism / area of larger prism
![k^2 = 882 / 1058 = 441/529\\k = \sqrt{ 441/529} \\k = 21/23](https://tex.z-dn.net/?f=k%5E2%20%3D%20882%20%2F%201058%20%3D%20441%2F529%5C%5Ck%20%3D%20%5Csqrt%7B%20441%2F529%7D%20%5C%5Ck%20%3D%2021%2F23)
Thus, correct option is B 21/23.
Answer:
2.16 s
Step-by-step explanation:
When it hits the ground, height h=0 hence
0=45-10t-5t^{2}
5t^{2}+10t-45=0
t^{2}+2t-9=0
Using quadratic formula
x=-1+\sqrt 10\\ x=-1-\sqrt 10
Since time can't be negative, -1+\sqrt 10
t=2.16 s
It should be noted that the expression that can be used to identify the x-values for which f(x)>-2 will be -2 <= x <= 2. This is illustrated in the graph.
<h3>How to explain the information?</h3>
It should be noted that a graph is a diagram that is used to show the relationship that exists between the data presented or the information.
In this case, ut should be noted that the expression that can be used to identify the x-values for which f(x)>-2 will be -2 <= x <= 2. This is illustrated in the graph.
The graph is attached below.
Learn more about expressions on:
brainly.com/question/723406
#SPJ1
Answer:
2nd option
Step-by-step explanation:
- 5 =
← in the form ![\frac{a}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bb%7D)
![\qquad\qquad\huge\underline{{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D)
Let's solve ~
![\qquad \tt \dashrightarrow \:\tt(6x {}^{4} −2x {}^{3} +7x {}^{2} −x) + ( 7x {}^{4} + 2x {}^{3} −5x + 7)](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%5Ctt%286x%20%7B%7D%5E%7B4%7D%20%E2%88%922x%20%7B%7D%5E%7B3%7D%20%20%2B7x%20%7B%7D%5E%7B2%7D%20%E2%88%92x%29%20%2B%20%28%207x%20%7B%7D%5E%7B4%7D%20%2B%202x%20%7B%7D%5E%7B3%7D%20%E2%88%925x%20%2B%207%29)
![\qquad \tt \dashrightarrow \:\tt6x {}^{4} −2x {}^{3} +7x {}^{2} −x + 7x {}^{4} + 2x {}^{3} −5x + 7](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%5Ctt6x%20%7B%7D%5E%7B4%7D%20%E2%88%922x%20%7B%7D%5E%7B3%7D%20%20%2B7x%20%7B%7D%5E%7B2%7D%20%E2%88%92x%20%2B%20%207x%20%7B%7D%5E%7B4%7D%20%2B%202x%20%7B%7D%5E%7B3%7D%20%E2%88%925x%20%2B%207)
Now, move all like terms aside :
![\qquad \tt \dashrightarrow \:6 {x}^{4} + 7 {}x^{4} - 2 {x}^{3} + 2 {x}^{3} + 7 {x}^{2} - x - 5x + 7](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A6%20%7Bx%7D%5E%7B4%7D%20%20%2B%207%20%7B%7Dx%5E%7B4%7D%20%20-%202%20%7Bx%7D%5E%7B3%7D%20%20%2B%202%20%7Bx%7D%5E%7B3%7D%20%20%2B%207%20%7Bx%7D%5E%7B2%7D%20%20-%20x%20-%205x%20%2B%207)
Add the like terms ~
![\qquad \tt \dashrightarrow \:13 {}x^{4} + 7 {x}^{2} + 6x + 7](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3A13%20%7B%7Dx%5E%7B4%7D%20%20%20%2B%207%20%7Bx%7D%5E%7B2%7D%20%20%20%2B%206x%20%2B%207)