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olga nikolaevna [1]
3 years ago
6

Can anyone help me solve the problem please and thanks.

Mathematics
1 answer:
grigory [225]3 years ago
5 0

Answer:

(A-1)/rt=P

Step-by-step explanation:

A= 1 + Prt     Subtract 1 from both sides

-1     -1

A - 1 = Prt     Divide rt on both sides

(A-1)/rt = P


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3 years ago
DIscrete Math
Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

  1. f : X \rightarrow Y is surjective implies there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y.
  2. If there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y, then f : X \rightarrow Y is surjective

Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

So, for every element y\in Y we have found that an element x\in X (recall that x=h(y)) such that y=f(x), which is equivalent to the fact that f is surjective. Therefore, the prove is complete.

3 0
3 years ago
20 POINTS !! IF YOU ANSWER THE QUESTIONS !
tatuchka [14]
12 the answer is 12 I know it
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3 years ago
5/6 = 1/3+d and x/x is a fraction
Alik [6]

\dfrac{1}{3}+d=\dfrac{5}{6}\qquad|-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1}{3}\\\\d=\dfrac{5}{6}-\dfrac{1\cdot2}{3\cdot2}\\\\d=\dfrac{5}{6}-\dfrac{2}{6}\\\\d=\dfrac{5-2}{6}\\\\d=\dfrac{3}{6}\\\\d=\dfrac{3:3}{6:3}\\\\\boxed{d=\dfrac{1}{2}}

7 0
3 years ago
A.
koban [17]

Answer: It would be 4b+44

Step-by-step explanation:

This is the distributive property! so a(b+c)=ab+ac

In this case–4b+44!

6 0
2 years ago
Read 2 more answers
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