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3 years ago

Can anyone help me solve the problem please and thanks.

Mathematics

1 answer:

grigory [225]3 years ago

5 0

Answer:

(A-1)/rt=P

Step-by-step explanation:

A= 1 + Prt Subtract 1 from both sides

-1 -1

A - 1 = Prt Divide rt on both sides

(A-1)/rt = P

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One number is 7 times another number. The product of the two numbers is 252. Find the two numbers.

Nitella [24]

Step-by-step explanation:

x =7y ----(1)

xy=252 ----(2)

(1) into (2):

(7y)(y) = 252

$7 {y}^{2} = 252 \\ 7y = \sqrt{252}$

7y=15.874....

y=2.27

y value into (1)

x= 7(2.268)

x=15.87

the two numbers are 15.87 and 2.27 (Ans)

6 0

2 years ago

Madeleine owes $36,000 to a private lender. The debt grows with 12% annual interest that compounds every week. How much will Mad

viva [34]

Answer:

A= $40584.28

Step-by-step explanation:

P = 36000

r = 12% = 0.12

n = 52 weeks

t = 1

$A = P(1 + \frac{r}{n})^{nt}\\$

$=36000(1 + \frac{0.12}{52})^{52 \times 1}\\\\=36000 (1.002307)^{52}\\\\=36000 \times 1.12734\\\\=40584.28$

7 0

3 years ago

Lauren Michel lends $17,000 at a rate of 10.7% .

Maru [420]

Given:
Principal = 17,000
rate = 10.7%
term = x/360
interest = 1,121.72

Interest = Principal * rate * term
1,121.72 = 17,000 * .107 * x/360
1,121.72 = 1,819x / 360
1,121.72 * 360 = 1,819x
403,632 / 1,819 = x
221.90 = x

Lauren Michelle will have to wait 222 days for her investment to earn $1,121.72

Given:
Principal = x
rate = 9%
term = 10 months
interest = 1,687.50

Interest = Principal * rate * term
1,687.50 = x * 0.09 * 10/12
1,687.50 = x * 0.075
1,687.50 / 0.075 = x
22,500 = x

The amount Sandra Leatherwood invested was $22,500.

7 0

3 years ago

What is 2logx−logy+2logz written as a single logarithm? log(xz)^2/y log2x/2yz logx^2y/z^2 logx^2/yz^2

Klio2033 [76]

Answer: $\log\dfrac{x^2z^2}{y}$

Step-by-step explanation:

Properties of logarithm:

$(i)\ \ n\log a = a^n\\\\ (ii)\ \ \log m +\log n =\log (mn)\\\\ (iii)\ \ \log m-\log n =\log\dfrac{m}{n}$

Consider,

$2\log x-\log y+2 \log z\\\\ =\log x^2-\log y+\log z^2\ \ \ \ \text{[By (i)]}\\\\= \log x^2+\log z^2-\log y\\\\=\log(x^2z^2)-\log y\ \ \ \ [\text{By } (ii) ]\\\\=\log(\dfrac{x^2z^2}{y}) \ \ \ \ [\text{By (iii)}]$

3 0

3 years ago

I really need help- eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Juliette [100K]

Answer:

-2, -5, 2, then 5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers