Which set of ordered pairs does NOT represent a function?

Use the data you've found up to this point to fill in the final column. c =, d =

polet [3.4K]

Answer:

we need the data to answer your question

Step-by-step explanation:

3 0

3 years ago

A movie theater sells morning tickets (m) for $4 and regular tickets (e) for $6. During one week, the theater earned $6000. The

grin007 [14]

Answer:

Step-by-step explanation:

8 0

3 years ago

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Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo

NNADVOKAT [17]

Answer:

a

$P(a | e') = 0.22$

$P(b | e') = 0.28$

$P(c | e') = 0.33$

b

$P(a | e' , d' , b') = 0.57$

Step-by-step explanation:

From the question we are told that

The probabilities are

Supplier chosen A B C

Probability P(a) = 0.20 P(b) = 0.25 P(c) = 0.15

D E

P(d) = 0.30 P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(a | e') = \frac{P (a \ and \ e')}{P(e')}$

$P(a | e') = \frac{P (a)}{P(e')}$

$P(a | e') = \frac{P (a)}{1- P(e)}$

=> $P(a | e') = \frac{ 0.20}{1- 0.10}$

=> $P(a | e') = 0.22$

Generally the new probability of companies B being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(b | e') = \frac{P (b \ and \ e')}{P(e')}$

$P(b | e') = \frac{P (b)}{P(e')}$

$P(b | e') = \frac{P (b)}{1- P(e)}$

=> $P(b | e') = \frac{ 0.25}{1- 0.10}$

=> $P(b | e') = 0.28$

Generally the new probability of companies C being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(c | e') = \frac{P (c \ and \ e')}{P(e')}$

$P(c | e') = \frac{P (c)}{P(e')}$

$P(c | e') = \frac{P (c)}{1- P(e)}$

=> $P(c | e') = \frac{ 0.15}{1- 0.10}$

=> $P(c | e') = 0.17$

Generally the new probability of companies D being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(d | e') = \frac{P (d \ and \ e')}{P(e')}$

$P(d | e') = \frac{P (d)}{P(e')}$

$P(d | e') = \frac{P (d)}{1- P(e)}$

=> $P(d | e') = \frac{ 0.30}{1- 0.10}$

=> $P(c | e') = 0.33$

Generally the probability that B, D , E are not chosen this year is mathematically represented as

$P(N) = 1 - [P(e) +P(b) + P(d) ]$

=> $P(N) = 1 - [0.10 +0.25 +0.30 ]$

=> $P(N) = 0.35$

Generally the probability that A is chosen given that E , D , B are rejected this year is mathematically represented as

$P(a | e' , d' , b') = \frac{P(a)}{P(N)}$

=> $P(a | e' , d' , b') = \frac{0.20 }{0.35 }$

=> $P(a | e' , d' , b') = 0.57$

5 0

3 years ago

Examine the following table, which defines the relationship y= f(x). Then, answer the question.

erastova [34]

The slope of the function is most positive either side of x=0 and x=2π.

On the interval [0, π/4], the average slope is $\dfrac{(\frac{\sqrt{2}}{2})}{(\frac{\pi}{4})} = \dfrac{2\sqrt{2}}{\pi}$

On the interval [7π/4, 9π/4], the average slope is $\dfrac{(\frac{\sqrt{2}}{2}-\frac{-\sqrt{2}}{2})}{(\frac{9\pi}{4}-\frac{7\pi}{4})}=\dfrac{2\sqrt{2}}{\pi}$

The average rate of change is highest on the intervals [0, π/4] and [7π/4, 9π/4].

4 0

3 years ago

Simplify 10d-3d ? Pls tell me I need help on this

Mariana [72]

Answer:

$7d$

Step-by-step explanation:

$10d-3d = 7 d$

hope it's helpful dear :)

3 0

3 years ago

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