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Charra [1.4K]
3 years ago
11

Simplify 10d-3d ? Pls tell me I need help on this

Mathematics
2 answers:
Mariana [72]3 years ago
3 0

Answer:

7d

Step-by-step explanation:

10d-3d  = 7 d

hope it's helpful dear :)

svetoff [14.1K]3 years ago
3 0

The answer to this question is:

7d

In this equation they want you to subtract 10 from 3 and that is 7. Make sure the two letters are the same. If they are you can simplify. If they are different letters you can not simplify further.

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The tree diagram below illustrates the possible outcomes of three tosses of a balanced coin. What is the probability that “heads
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I’m pretty sure its B.1/4
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3 years ago
Will the Brainliest answer!!!<br><br> solve for x and y.<br><br> 946x+642y=911
Ronch [10]

While you cannot solve 946x+642y=911 for numerical values of x and y, you can indeed solve 946x+642y=911 first for x and then for y:

-911 - 642y

For x: 946x+642y=911 becomes 946x = 911 - 642y, or x = ------------------

946

911-946x

For y: 946x+642y=911 becomes 642y = 911-946x, or y = ---------------

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8 0
4 years ago
Read 2 more answers
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
Quiz 2: percent and percentage
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Answer:

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Step-by-step explanation:

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Is there a picture or options to this ?
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