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mezya [45]
3 years ago
13

Need Help ASAP

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
The sum of the interior angles of a triangle is 180 degrees

2x-9+3x+x+3=180
6x-6=180
6x=186
x=31

A=2(31)-9
A=62-9
A=53
You might be interested in
The radius of a cylinder is 3 cm and the height is 6 cm.
mars1129 [50]

Answer:

Lateral Area of a Cylinder = 2πrh

=2π x 3 x 6

=36π

Option D

4 0
2 years ago
Which equation represents a parabola?
Evgesh-ka [11]

Answer:

(B)

Step-by-step explanation:

we know that standard equation of parabola y²= 4x or x² = 4y .

So option (B) is correct .

Hope it's helpful

5 0
3 years ago
Find the value of 7u+7 given that -3u-5=4
Serga [27]

Answer:

14

Step-by-step explanation:

-3u = 4+5

-3u = 9

u = -3

7u + 7

7(u +1) = 7(-3+1)

7(-2)

14

3 0
2 years ago
5) Find the equation of the line going through the point (4,1) and<br> perpendicular to y = - 3x +7
vovangra [49]

Answer:

3y=x-1 OR y=⅓x-⅓

Step-by-step explanation:

Lets call the equation y=-3x+7 line l1

the other line passing through (4,1) l2

If two lines are perpendicular,then the product of their roots=-1

That is m(l1)×m(l2)=-1

Slope of l1=-3 therefore slope of l2=-1÷-3=⅓

Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form

y-y1=m(x-x1)

y-1=⅓(x-4)

3y-3=x-4

3y=x-4+3

3y=x-1 OR y=⅓x-⅓

6 0
3 years ago
Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui
Vesnalui [34]
<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

Also, Area of the box  = S x S x H  =  S²H

⇒ S²H = 2000

\implies H = \frac{2000}{S^2}

Substituting the value of H in (1), we get:

A = S^2 + 4 SH =  S^2 + 4 S(\frac{2000}{S^2}) =  S^2 + (\frac{8000}{S})\\\implies A  =  S^2 + (\frac{8000}{S})

Now, to minimize the area put :

(\frac{dA}{dS} ) = 0 \implies 2S  - \frac{8000}{S^2}  = 0\\\implies S^3 = 4000\\\implies S  = 15.874 \approx 16 cm

Putting the value of S  = 15.874 cm in the value of H , we get:

\implies H = \frac{2000}{S^2}  =  \frac{2000}{(15.874)^2} = 7.8937 cm

Hence, the dimensions of the given rectangular box are:

L  =   15.874 cm

B  = 15.874 cm

H = 7.8937 cm

3 0
3 years ago
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