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mezya [45]
3 years ago
13

Need Help ASAP

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
The sum of the interior angles of a triangle is 180 degrees

2x-9+3x+x+3=180
6x-6=180
6x=186
x=31

A=2(31)-9
A=62-9
A=53
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Aisha organized her books for 5 hour and her coin collection for 3 hour. 7 What is the best estimate for the total time Aisha sp
MAVERICK [17]

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about 8 hours

Step-by-step explanation:

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4 years ago
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What is 21x^6y^5 divided by 14x^y^9 will make brainliest lot of points on the line too
Fiesta28 [93]

Answer:

\dfrac{3x^4}{2y^4}

Step-by-step explanation:

\dfrac{21x^6y^5}{14x^2y^9}= \\\\\\\dfrac{21}{14}\cdot \dfrac{x^6}{x^2} \cdot \dfrac{y^5}{y^9}= \\\\\\\dfrac{3x^4}{2y^4}

Hope this helps!

5 0
3 years ago
Giúp mìn vs mngggggg
zvonat [6]

Answer:

136.99

Step-by-step explanation:

Đây là một câu hỏi dễ chỉ cần sử dụng máy tính

3 0
3 years ago
Jacque estimates the square root of 125 in the following way:
mafiozo [28]

Answer:

<h2>5</h2>

Step-by-step explanation:

<h2>√125/5 = √25 since 125/5 = 25</h2><h2>√25 = 5</h2><h2 /><h2>Hopes this helps. Mark as brainlest plz!</h2>
5 0
3 years ago
You are trying to determine if you should accept a shipment of eggs for a local grocery store. About 4% of all cartons which are
padilas [110]

Answer:

0.8809

Step-by-step explanation:

Given that:

The population proportion p = 4% = 4/100 = 0.04

Sample mean x = 16

The sample size n = 300

The sample proportion \hat  p =\dfrac{x}{n}

= 16/300

= 0.0533

∴

P(\hat p \leq 0.0533) = P\bigg ( \dfrac{\hat p - p}{\sqrt{\dfrac{P(1-P)}{n}}}\leq\dfrac{0.0533 - 0.04}{\sqrt{\dfrac{0.04(1-0.04)}{300}}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.04(0.96)}{300}}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.0384}{300}}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{1.28 \times 10^{-4}}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{0.0113}}\bigg )

P(\hat p \leq 0.0533) = P\bigg ( Z\leq1.18}\bigg )

From the z tables;

= 0.8809

OR

Let X be the random variation that follows a normal distribution;

Then;

population mean \mu = n × p

population mean \mu = 300 × 0.04

population mean \mu = 12

The standard deviation \sigma = \sqrt{np(1-p)}

The standard deviation  \sigma = \sqrt{300 \times 0.04(1-0.04)}

The standard deviation \sigma = \sqrt{11.52}

The standard deviation  \sigma = 3.39

The z -score can be computed as:

z = \dfrac{x - \mu}{\sigma}

z = \dfrac{16 -12}{3.39}

z = \dfrac{4}{3.39}

z = 1.18

The required probability is:

P(X ≤ 10) = Pr (z  ≤ 1.18)

= 0.8809

5 0
3 years ago
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