X = k and y = 0 is the solution
Well to factor a trinomial (Which is in the form ax^2 + bx + c) You would have to bring the A over to c so you can get x^2 alone. (If their isn't a gcf) You could also try to find what multiplys ac to add to b. but since that is not possible you would rewrite it x^2 -27x + 72 ( by multiplying the a to c) The you would rework it as normal (whatever two numbers multiply to 72 and add to -27. Which would be (x-3)(x-24). Then you would divide by the original A (x-3/18)(x-24/18). Then you would simplify that. (x-6)(x-4/3) and you would take any extra denominators and bring it to the front of the x. Making it (x-6)(3x-4)
<h2>
Step-by-step explanation:</h2>
A: f(x)=8x-2
1. Switch the f(x) to y
y=8x-2
2. Switch y to x and x to y
x=8y-2
3. Solve for y:
------------------------------
1. Add 2 to both sides.
x=8y-2
+2 +2
2. Divide both sides by 8.
x+2=8y
--- ---
8 8
1/8x+1/4=y
3. Write in f-inverse form
f^-1(x)=1/8x+1/4
B: g(x)=2/3x+6
1. Switch the g(x) to y
y=2/3x+6
2. Switch y to x and x to y
x=2/3y+6
3. Solve for y:
------------------------------
1. Subtract 6 from both sides.
x=2/3y+6
-6 -6
2. Multiply both sides by 3/2 (to cancel out the 2/3)
x-6=2/3y
2/3x-4=y
3. Write in f-inverse form
g^1(x)=2/3x-4
C: h(x)-4x-12
1. Switch the h(x) to y
y=-4x-12
2. Switch y to x and x to y
x=-4y-12
3. Solve for y:
------------------------------
1. Add 12 to both sides.
x=-4y-12
+12 +12
2. Divide both sides by -4
x+12=-4y
------ ---
-4 -4
-1/4x-3=y
3. Write in h-inverse form
h^2(x)=-1/4/x-3
