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tino4ka555 [31]
3 years ago
14

P=3x+2y find the maximum value of the function

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

Step-by-step explanation:

Without a domain you cannot answer this question.  We can find the maximum value of the function if the spread of acceptable input values (x-values) is specified and the range is likewise specified.

For example, if acceptable input values x are {0, 2} and acceptable input values y are {4, 5}, then the maximum value of p would be 3(2) + 2(5), or 16.

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Shankar is teaching 2 courses, let us call them 435 and FYS. 435 has 3 sophomores, 8 juniors and 13 seniors; FYS has 5 sophomore
Mice21 [21]

Answer:

The probability that both students are of the same type is \frac{149}{432}.

Step-by-step explanation:

The students in 435 are: {3 sophomores, 8 juniors and 13 seniors}

Number of students in 435 = 3 + 8 + 13 = 24

The students in FYS are: {5 sophomores, 7 juniors and 6 seniors}.

Number of students in FYS = 5 + 7 + 6 = 18

The teacher picks 1 student from each class.

The probability that both students are of the same type is:

P (Same type students) = P (Both are Sophomores) + P (Both are Juniors)

                                                     + P (Both are Seniors)

= P (Sophomore ∩ Course 435) × P (Sophomore ∩ Course FYS)

         + P (Junior ∩ Course 435) × P (Junior ∩ Course FYS)

               + P (Senior ∩ Course 435) × P (Senior ∩ Course FYS)

                       =[(\frac{3}{24} )\times(\frac{5}{18})]+[(\frac{8}{24} )\times(\frac{7}{18})]+[(\frac{13}{24} )\times(\frac{6}{18})]\\=\frac{15+56+78}{432}\\ =\frac{149}{432}

Thus, the probability that both students are of the same type is \frac{149}{432}.

3 0
4 years ago
Robert has a monthly income of $1,650.00. His monthly mortgage payment is $675.00. What percentage of his income does Robert spe
rodikova [14]
40% of his income goes towards his mortgage.
7 0
3 years ago
Read 2 more answers
You want to convert 1 Kilogram to milligrams. You already know that 1 kilogram = 1,000 grams. Explain how knowing hat 1 gram = 1
Alenkasestr [34]
The answer Is one million milligrams (tongue twister) to find this out you simply know that a kilogram is 1000 times a gram and a gram is a thousand times a milligram.
1000x1000= 1,000,000
Your welcome.
BRAINLIEST PLEASE
4 0
3 years ago
Im begging you PLS answer my questions
Mandarinka [93]

Answer:

sure but where are the questions??

Step-by-step explanation:

8 0
3 years ago
The number of fish in a small bay is modeled by the function F defined by F(t)=10 (t3 â 12t2 + 45t +100), where t is measured in
RSB [31]

The graph of the given function is attached showing characteristics of the function.

The correct responses are;

  • (a) F'(4) = -30 means that <u>on day 4, the number of fish in the bay is decreasing at a rate of 30 fish per day</u>.
  • (b) Over the interval 0 ≤ t ≤ 8 the absolute minimum number of fish in the bay is;<u> 1,000</u>.
  • (c) The values of <em>t</em> at which the rate of change is decreasing is; <u>3 ≤ t ≤ 8</u>
  • (d) The rate of change of the number of pelicans flying near is; P' =  <u>10·(3·c² - 24·c  + 45)</u>

Reasons:

The given function is; f(t) = 10·(t³ - 12·t² + 45·t + 100)

Where;

t = Number of days

0 ≤ t ≤ 8

(a) The derivative of the given function is presented as follows;

F'(t) = 10 × (3·t² - 2×12·t + 45) = 10·(3·t² - 24·t  + 45)

Therefore;

F'(4) = 10 × (3 × 4² - 24 × 4  + 45) = -30

Therefore F'(4) = -30 means that on day 4, the <u>number of fish in the bay is decreasing at 30 fish per day</u>.

(b) The absolute minimum is given as follows;

At a minimum or maximum value, F'(t) = 10·(3·t² - 24·t  + 45) = 0

Which gives;

3·(t - 5)·(t - 3) = 0

t = 5, or t = 3

At t = 5, we have;

f(5) = 10 × (5³ - 12 × 5² + 45 × 5 + 100) = 1,500

At t = 3, we have;

f(3) = 10 × (3³ - 12 × 3² + 45 × 3 + 100) = 1,540

Therefore, f(5) = 1,500 is a local maximum

However, at x = 0, we have;

f(0) = 10 × (0³ - 12 × 0² + 45 × 0 + 100) = 1000

At x = 8, we have;

f(8) = 10 × (8³ - 12 × 8² + 45 × 8 + 100) = 2,040

Therefore, the absolute minimum is given at t = 8, where f(t) = <u>1,000</u>

(c) The values of <em>t</em> at which the rate of change in the number of fish in the

bay is decreasing is between the local maximum at t = 3, and the local

minimum at t = 5, which gives;

The rate of change of the number of fish is decreasing for values of t in the range;

  • <u>3 ≤ t ≤ 5</u>

(d)  P = 10·(t³ - 12·t² + 45·t + 100)

P' =  10·(3·t² - 24·t  + 45)

At time t = c, we have;

  • P' =  10·(3·c² - 24·c  + 45)

<em>Based on a similar question online, we have;</em>

<em>(c) The interval over which the rate of change is decreasing</em>

<em>(d) The rate of change of the number of pelicans flying near the bay at t = c</em>

Learn more about differentiation of functions here:

brainly.com/question/1422315

5 0
2 years ago
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