Answer and step-by-step explanation:
Break the bracket out would be the first step to evaluate this expression:
3(x-1)
= 3x - 3
Hope this helped :3
The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)
8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)
So:
a(n) = a(n-1) + a(n-2)^2
Lets check: 88+24^2= 664
664+88^2= 8408
Answer:
Step-by-step explanation:

X - Heights of women aged 20 to 29: X is N(64, 2.7)
Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)
a) X=6'=72"
Z=
b) Y = 72"
z=
c) 72' women can be taken as very tall but men moderately taller than average
d) Y<5'5" =65"
Z<
e) X>73"
Z>
Almost 0% can be taken
f) IQR =Q3-Q1
Z scores =