A line contains the points (−26, −37) and (−32, −61) .

2 answers:

8 0

The slope is 4
To find the slope formula is y2-y1/x2-y1 so you will have -61- -37 / -32- -26 which will give you 24/ 6 and when you simplify is 4

Morgarella [4.7K]3 years ago

3 0

Answer:

The slope of the line containing the points (-26,-37) and (-32,-61) is 4

Step-by-step explanation:

Given:

Two points of the line (-26,-37) and (-32,-61)

To find:

Slope(m) of the line =?

Solution:

The Equation of slope of two points is

$Slope m=\frac{(y_2-y_1)}{(x_2-x_1)}$

Let (-26,-37) be $(x_1,y_1)$

and (-32,-61) be $(x_2,y_2)$

Now substituting the values ,

$m=\frac{(-61+37)}{(-32+26)}$

$m=\frac{-24}{-6}$

m=4

Thus the slope of the line is 4

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Find the missing side lengths

Alik [6]

For this triangle in particular, we can use the special rules of a 30-60-90 triangle

This says:
The opposite side of 30° is: x
The opposite side of 60° is: x * sqrt(3)
The opposite side of the 90° is: 2x

We have our side length for 90° so we just have to work backwards
To find our 30° side length we must divide by 2
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Which means your y = 4

Now that we have our 30° side length we can just multiple it by sqrt(3)

That means your x = 4 sqrt(3)

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Answer:

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