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2 years ago

What is the value of the expression below? (0−3)−8(12+4)

Mathematics

2 answers:

butalik [34]2 years ago

6 0

Answer:

-131

Step-by-step explanation:

(0 − 3) − 8(12 + 4) =

= -3 - 8(16)

= -3 - 128

= -131

olga_2 [115]2 years ago

6 0

Answer:

The exact value using trigonometric identities/just evaluating would be -131

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3 years ago

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EleoNora [17]

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3 years ago

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69. REAL-WORLD APPLICATIONS

svp [43]

Answer:

Cost of per session the average rate is $45.

Step-by-step explanation:

It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.

It is required to find what is the cost per session.

Step 1 of 1

It is given that a gym membership with two personal training session cost $125, while gym membership with five personal training sessions cost $260.

To find the cost of per session calculate the average rate.

Now let $f(x)$ be the cost per session use the for the average rate of change, and the input value is the number of personal traings x.

$m=\frac{f\left(x_{2}\right)-f\left(x_{1}\right)}{x_{2}-x_{1}}$$

Now substitute, $125 for $$f\left(x_{2}\right)$ , 260 for $f\left(x_{1}\right), 2$ for $x_{1}$ and 5 for $x_{2}$ then,

$m=\frac{260-125}{5-2}$\$$\begin{aligned}&=\frac{135}{3} \\&=45\end{aligned}$$

Cost of per session the average rate is $45.

3 0

2 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago

Find the vertex and length of the latus rectum for the parabola. y=-1/2(x-2)^2+8

victus00 [196]

Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)² ↔ (y-k) = a(x-h)²

This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)

Latus rectum: y-value = 15/2

Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then
Latus rectum = 5

4 0

3 years ago