Answer:
Step-by-step explanation:
11.7
Answer:
The profit will be maximum on x = 250.
Step-by-step explanation:
From the given information:
Revenue = 1500x - x²
Cost = 1500 + 1000x
As we know that
Profit = Revenue - Cost ; Let say it equation 1
Then after putting the values of revenue and cost in equation 1 we have:
Profit = (1500x - x²) - (1500 + 1000x)
Profit = 1500x - x² - 1500 - 1000x
Profit = -x² + 500x - 1500
We know that at the max or min the slope of the graph formed by the profit function will be zero, therefore we find the slope of profit function by taking the first derrivative w.r.t. x as under:
d(Profit)/dx = d/dx(-x² + 500x - 1500)
d(Profit)/dx = -2x + 500
By putting the above slope equal to zero we get:
d(Profit)/dx = -2x + 500 = 0
-2x + 500 = 0
-2x = -500
x = 250
Therefore it is concluded that the profit will be maximum when x will be equal to 250.
Answer:
Step-by-step explanation:
So, it's x*x+x*-3+-4*x+3*-3
That simplifies to x^2 - 7x + 12
Answer: C) Contrapositive
The original conditional is in the form "If P, then Q"
The contrapositive is in the form "If not Q, then not P"
You flip the order of P and Q, and you also negate each piece. The original conditional and contrapositive can be proven to have the same truth values through the use of a truth table.
Set 500 to sum of distances traveled by both cars.
