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Dvinal [7]
2 years ago
15

How do you find the volume of a shape with 2 different heights and 1 extra block on the width??

Mathematics
2 answers:
shusha [124]2 years ago
6 0

Question unclear

Step-by-step explanation:

If it is a trapezoid, you can simply find the average of the two base lengths, but I can't help much without seeing the shape.  Please add a picture of the shape.

Gre4nikov [31]2 years ago
4 0

Answer:

If it is a trapezoid, you can simply find the average of the two base lengths, but I can't help much without seeing the shape.  Please add a picture of the shape.

Step-by-step explanation:

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3 years ago
What is the distance between the two points (-8,-6) and (-2,4)?
MAVERICK [17]

Answer:

\sqrt{136} = 11.66 units

Step-by-step explanation:

distance between 2 points (a,b) and (c,d) = \sqrt{(a^{2}-c^{2} ) +(b^{2}-d^{2} ) }

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3 years ago
In triangle ΔABC, ∠C is a right angle and CD is the height to
Zina [86]

Answer:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles m\angle CDB=m\angle CDA=90°

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha

From ΔCBD,

m\angle CBD is same as m\angle B.

So, m\angle CBD=90-\alpha

m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha

Now, from ΔCAD,

m\angle CAD is same as m\angle A

So, m\angle CAD=\alpha

m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha

Hence, the unknown angles of both the triangles are:

m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha

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2 years ago
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Nataly [62]

Answer:

B?????

Step-by-step explanation:

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3 years ago
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2 years ago
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