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vazorg [7]
3 years ago
11

What is the volume of the rectangular prism?

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0
It’s (B.)
In other word 63 yd^3
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Inga [223]

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Step-by-step explanation:

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3 years ago
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Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche
allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0
3 years ago
Which of these descriptions matches the graph?
qwelly [4]

The correct answer is A. Jimmy is running late, so he starts to run to school  but needs to take breaks.

Explanation:

The graph shows the distance in axis y and the time in axis x. Additionally, the graph presents different sections from A to E. In this, the sections A, C, and E show an increase in the distance from home, this implies there was movement. Moreover, the speed (distance traveled in time) is higher in sections C and E than in A because the distance increases in a shorter time. Also, in sections D and B there is no movement as time continues but the distance is the same. In this context, the description that best matches the graph is "Jimmy is running late, so he starts to run to school  but needs to take breaks" because this is the only option that includes the breaks or lack of movement in sections B and D. Also, the changes in speed are likely to occur in this scenario.

7 0
3 years ago
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Use a calculator to find the value of each expression. Round your answer to the nearest hundredth.
inysia [295]

Answer:

Arcsin(1/5) = 0.20

Arcsin(-0.34) = -0.35

Arcsin(0.6) = 0.64

Step-by-step explanation:

Using a calculator we can find the value of each expression:

Arcsin(1/5) = 0.20135792079, rounding to the nearest hundredth we have that: Arcsin(1/5) = 0.20.

Arcsin(-0.34) = -0.346916897527, rounding to the nearest hundredth we have that: Arcsin(-0.34) = -0.35

Arcsin(0.6) = 0.643501108793, rounding to the nearest hundredth we have that: Arcsin(0.6) = 0.64

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marysya [2.9K]

Answer:

Sometimes

Step-by-step explanation:

because you never know how many way you can do it

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2 years ago
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