Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Answer:
I think it’s the associative property
X=1.3
Hope this helps I not I’m truly sorry
Answer:
2
Step-by-step explanation:
Fill in each function's argument and do the arithmetic.

Answer:
The mean and standard deviation of Y is $6.56 and $2.77 respectively.
Step-by-step explanation:
Consider the provided information.
Let Y represent their profit on a randomly selected pizza with this promotion.
The company is going to run a promotion where customers get $2 off any size pizza.
Therefore, 

So the mean will be reduced by 2.



If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.
Therefore 
Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.