The first question is c i believe, I dont have time to answer the others
To find if a point is a solution to a system of equations, we need to plug in the x and y values of the point into each equation, and see if the equation is true.
Let's plug it into the first equation first:
-2(3) - 4(-2) might = 2
-6 + 8 = 2
The first equation is true.
Now, we need to check the second equation:
3(3) + 4(-2) might =8
9 - 8 does not = 8
Therefore, even if the point satisfies one equation, it does not satisfy the other. We can conclude that this is not a solution.
Hope this helps!
Answer:
First do the case in which none of the digits is 0.
There are 9 ways to choose the digit that repeats 3 times and 8 ways to pick the other, after this there are 4 ways to order the digits. So 9×8×4.
Now we look at the cases in which the digit 0 repeats 3 times. Clearly the 9 numbers are 1000,2000,3000,…,9000.
Lastly we look at the cases in which 0 appears once. There are 9 ways to pick the other digit and 3 ways to order.
So the final answer is 9×8×4+9+9×3.
Answer:
Step-by-step explanation:
<u>Given equation</u>
- f(t) = 2^(kt)
- f - number of cells, t - number of months, k- coefficient
<u>We got 32 cells in the first month. It means:</u>
<u>Using these numbers we can find the coefficient k:</u>
- 32 = 2^(k*1)
- 2^5 = 2^k
- k = 5
<u>Then the equation becomes:</u>
<u>Average time is 9 months, we can calculate the number of cells:</u>
- f(9) = 2^(5*9) = 2^45 ≈ 3.5*10^13
<span>He has failed to consider the number 0, which is a whole number but not a natural number.</span>
