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Verizon [17]
3 years ago
13

According to a recent study, US adults spent on average 29 hours per month using the PC internet. The time spent on the PC inter

net follows a normal distribution with mean 29 hours per month and standard deviation 12 hours per month.What percent of US adults spend above 29 hours per month on PC internet? g
Mathematics
1 answer:
Andrei [34K]3 years ago
5 0

Answer: The percent of US adults spend above 29 hours per month on PC internet = 50%

Step-by-step explanation:

Given: , US adults spent on average 29 hours per month using the PC internet.

As the me spent on the PC internet follows a normal distribution.

And there is 50% of the population lies above the mean and below the mean.

Then, the percent of US adults spend above 29 hours per month on PC internet = 50%

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Greg buys a home for $328,500. His home is predicted to increase in value 4% each year. What is the predicted value of his home
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The initial value of the Greg`s home: $328,500. If his home is predicted to increase in value 4% each year, that means that the value will rise 1.04 times every year.
The predicted value after 30 years:
$328,500 * ( 1 + 0.04 ) ^30 = 
= $328,500 * 1.04^30 = 
= $328,500 * 3.2434 = 
= $1,065,456.
Answer: The predicted value of his home in 30 years is $1,065,456.
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Your answer is Option C) 9

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you receive an allowance of a penny the first day of the month and the amount you receive doubles every day for the rest of the
nignag [31]

Answer:

56

Step-by-step explanation:

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3 years ago
Solve the system of equations.
professor190 [17]

Answer:

Hello,

-4 x + 11 y = 15 ⇔ -4 (2 y) + 11 y = 15 ⇔ 3 y = 15 ⇔ y = 5

x = 2 y = 10

Step-by-step explanation:

4 0
3 years ago
A sparkling-water distributor wants to make up 400 gal of sparkling water to sell for $8.00 per gallon. She wishes to mix mix th
Alex787 [66]

The sparkling-water distributor should use 160 gallons of $ 14 and 80 gallons of $ 3 and 160 gallons of $ 4.50

<em><u>Solution:</u></em>

Let "x" be the gallons of $ 14

Let "y" be the gallons of $ 3

Let "z" be the gallons of $ 4.5

<em><u>A sparkling-water distributor wants to make up 400 gal of sparkling water</u></em>

Therefore,

x + y + z = 400 --------- eqn 1

<em><u>She must use twice as much of the $4.50 water as the $3.00 water</u></em>

gallons of $ 4.5 = twice of gallons of $ 3

z = 2y --------- eqn 2

<em><u>A sparkling-water distributor wants to make up 400 gal of sparkling water to sell for $8.00 per gallon</u></em>

Therefore, we frame a equation as:

x \times 14 + y \times 3 + z \times 4.5 = 400 \times 8

14x + 3y + 4.5z = 3200 ----------- eqn 3

<em><u>Substitute eqn 2 in eqn 3</u></em>

14x + 3y + 4.5(2y) = 3200

14x + 3y + 9y = 3200

14x + 12y = 3200

Divide both sides by 2

7x + 6y = 1600 -------- eqn 4

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + y + 2y = 400

x + 3y = 400

x = 400 - 3y ------- eqn 5

<em><u>Substitute eqn 5 in eqn 4</u></em>

7(400 - 3y) + 6y = 1600

2800 - 21y + 6y = 1600

15y = 1200

Divide both sides by 15

y = 80

<em><u>Substitute y = 80 in eqn 5</u></em>

x = 400 - 3(80)

x = 400 - 240

x = 160

<em><u>Substitute y = 80 in eqn 2</u></em>

z = 2(80)

z = 160

Thus she should use 160 gallons of $ 14 and 80 gallons of $ 3 and 160 gallons of $ 4.50

4 0
3 years ago
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