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wolverine [178]
3 years ago
14

Help plz One equation with decimals f.) 4.5x + 9 = 40

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

x = 6.8

Step-by-step explanation:

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2x - 3y = 8 // <br><br> Find y
konstantin123 [22]

Answer:

y = -\frac{2}{3} x - \frac{8}{3}

Step-by-step explanation:

2x - 3y = 8\\

Isolate y

-3y = 8-2x\\-3y = -2x+8

Divide both sides of the equation by -3

\frac{-3y}{-3} = \frac{2x}{-3} +\frac{8}{-3} \\\\y = -\frac{2}{3} x - \frac{8}{3}

7 0
3 years ago
PLEASE HELP ME Given the equation fine f(6) <br><br> F(x)=-4x-1
velikii [3]

Answer:

-25 plug in 6 for x and minus one

Step-by-step explanation:

6 0
2 years ago
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hhhhhhhhhhhhhhhhuuuuuuuuuuuuuuuurrrrrrrrrrrrrrrrrryyyyyyyyyyyyyyyyyyyyyyy ppppppppppppppllllllllllllllllllllllllllllllllllllllll
zavuch27 [327]

Answer:

A. 3 1/4

Step-by-step explanation:

Convert the mixed numbers to improper fractions, then find the LCD and combine.

8 0
3 years ago
Read 2 more answers
Which co-ordinates do you plot to draw the graph of x + 2y = 3 ?
pychu [463]
Just subisute values that will work
one easy way is to make one sides equal to only one of the placeholders, like y, and then lug in values in for x exg
x+2y=3
subtract x from both sides
2y=3-x
divideb bith sides by 2
y=-1/2x+3
subsitute valudes for x and get values for y
if x=2 then
y=-1/2(2)+3
y==-1+3
y=2
when x=2, y=2
when y=0 then y=3
3 0
3 years ago
If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?
mihalych1998 [28]
Differentiating an integral removes the integral.

f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
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