Question

The quadrilateral is a rhombus. If EF = 13 and DF = 18, find EH to the nearest tenth.

Answer 1

Answer:

EH = 9.4

Step-by-step explanation:

A rhombus is a quadrilateral with equal length of sides.

Given that,  EF = 13 and DF = 18

⇒ DH = HF = $\frac{18}{2}$

             = 9

The property that the diagonals of a rhombus are at right angle to each other.

Thus, applying the Pythagoras theorem, we have;

$/hyp/^{2}$ = $/adj1/^{2}$ + $/adj2/^{2}$

$(EF)^{2}$ = $(EH)^{2}$ + $(HF)^{2}$

$(13)^{2}$ = $(EH)^{2}$ + $(9)^{2}$

169 =  $(EH)^{2}$ + 81

$(EH)^{2}$ = 169 - 81

           = 88

EH = $\sqrt{88}$

      = 9.381

The length EH is 9.4