All categories

3 years ago

Suppose you scored 78,78,and 79 on the first three tests. Is it possible

Mathematics

2 answers:

Mrrafil [7]3 years ago

6 0

Answer: No

Step-by-step explanation:

A B grade is 80%, to find the average you add all the numbers and divide by the amount of subjects. In this case it would be 79+79+78 divided by 3.

xxMikexx [17]3 years ago

4 0

Your average would be
83.75

You might be interested in

5(10k+1)+2(2+8k) simplify

iVinArrow [24]

Firstly expand it: 50k + 5 + 4 + 16k
Collect like terms: (50k + 16K) + (5 + 4)
Simplify: 66k + 9.

4 0

3 years ago

Emily buys a toaster during the sale off for 10% off if ellen pays 36$ what was the original price

LenaWriter [7]

Answer:

100%-10%=90%

90%=36$ what about 10%=4$

36$+4$=40$

5 0

2 years ago

Which ordered pair is a solution of the equation?<br> y = 3x+5

DedPeter [7]

Answer:

Step-by-step explanation:

Y=1/3y+-5/3

7 0

3 years ago

23 + 4.5 = 4.5 + 23 es un ejemplo de la propiedad

dybincka [34]

Step-by-step explanation:

ES UN EJEMPLO DE PROPIEDAD COMMULATIVE.

hola Hermano, cóme TE IIamas

donde vives?

6 0

3 years ago

Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)

borishaifa [10]

Answer:

Since,

$\frac{d}{dx}x^n = nx^{n-1}$

$\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))$

$\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}$

1) $y = 8x e^x$

Differentiating with respect to x,

$\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)$

2) $y = 5x e^{x^4}$

Differentiating w. r. t x,

$\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)$

3) $y = x^8 + \frac{5}{x^4}$

Differentiating w. r. t. x,

$\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}$

4) $f(t) = te^{11}-6t^5$

Differentiating w. r. t. t,

$f'(t) = e^{11} - 30t^4$

5) $g(p) = p\ln(2p+3)$

Differentiating w. r. t. p,

$g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)$

6) $z = (te^{6t}+e^{5t})^7$

Differentiating w. r. t. t,

$\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})$

7) $w =\frac{2y + y^2}{7+y}$

Differentiating w. r. t. y,

$\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}$

7 0

3 years ago